I also agree to A. The force will always pull back a lot deals with gravitational pull
Answer:
![\Delta K=0.15J](https://tex.z-dn.net/?f=%5CDelta%20K%3D0.15J)
Explanation:
The work-energy theorem states that the work done on the system is equal to its change of kinetic energy:
. This refers to the center of mass in the case of a system of particles. To calculate this work, we need to use the net Force on the system and the displacement of its center of mass:
![\Delta K=W=F_{net}d_{cm}=(10N-5N)(0.03m)=0.15J](https://tex.z-dn.net/?f=%5CDelta%20K%3DW%3DF_%7Bnet%7Dd_%7Bcm%7D%3D%2810N-5N%29%280.03m%29%3D0.15J)
D. The osculations show a variable rate of motion. Hope this helps:)
Given that,
Velocity , V = 20 m/s
Radius of curve, r = 50 m
Centripetal acceleration, ac = ?
since,
ac = V²/ r
ac = 20²/50
ac = 8 m/s²
The centripetal acceleration of car is 8 m/s².