Answer:
v = 8.8 m /s 
Explanation:
For listener and source going away from each other the formula of Doppler effect is as follows 

V is velocity of sound , v is velocity of listner and source of sound 
f₀ is apparent frequency and f is real frequency 
V = 343 , v = ? ,f = 210 , f₀ = 221
Put these value in the relation above 
![[tex]\frac{210}{221} = \frac{343-v}{343+v}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B210%7D%7B221%7D%20%3D%20%5Cfrac%7B343-v%7D%7B343%2Bv%7D) [/tex]
[/tex]
v = 8.8 m /s 
 
        
             
        
        
        
Answer:
 λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
            d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
            tan θ = y / L
            tan θ =  = sin θ
 = sin θ
            sin θ = y / L
we substitute
            = m λ
 = m λ
with the initial data we look for the distance between the lines
            d =  
            d = 1 656 10⁻⁹ 1.00 / 0.600
             d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
            λ = d y / L m
            λ = 1.09 10⁻⁶ 0.364 / 1.00 1
            λ = 3.9676 10⁻⁷ m
            λ = 3.967 10⁻⁷ m
          
we reduce nm
            λ = 396.7 nm
 
        
             
        
        
        
If magnification is less than one it means the image is the same exact size as the object.
        
             
        
        
        
Who was the proponent of the Neo-classicism? 
a) Claude Debussy 
b) Joseph Maurice Ravel 
c) Igor Stravinsky 
d) Arnold Schoenberg