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2 years ago

6.7 times 10^-5 in standard form

Mathematics

1 answer:

alexdok [17]2 years ago

8 0

Answer:

daw

Step-by-step explanation:

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Heather makes $6.50 per hour. Every three months, she is eligible for a 2% raise. How much will she make after 2 years if she ge

sammy [17]

Answer:

$7.62 per hour

Step-by-step explanation:

Since, Heather gets a raise every 3 months, in 2 years, she will get a raise 8 times (2years = 24 months, 24 divided by 3 is 8).

Now it becomes a compound growth problem. We can use the formula shown below to solve these type of problems.

$F=P(1+r)^t$

Where,

F is the future value (what we want to find)
P is the present rate ($6.5)
r is the rate of growth, in decimal (2% growth means 0.02)
t is the time frame, number of times compounding occurs (for our case we have figured it to be 8)

<u>Now plugging in all the info, we get the value of F:</u>

$F=P(1+r)^t\\F=6.5(1+0.02)^8\\F=6.5(1.02)^8\\F=7.62$

Thus, after 2 years, Heather's hourly rate will be $7.62

7 0

3 years ago

(4.04 LC)

sukhopar [10]

The answer will be B

4 0

2 years ago

Read 2 more answers

Find j. 6 + 2(3j – 2) = 4(1 + j)

Sindrei [870]

Answer:

j=1

Step-by-step explanation:

8 0

3 years ago

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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

2 years ago

3a−15=4a−3a I NEED HELP WITH THIS ASAP PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

GaryK [48]

Answer:

a = 15/2

Step-by-step explanation:

3a−15=4a−3a

Combine like terms

3a - 15 = a

Subtract 3a from each side

3a-3a−15=a−3a

-15 = -2a

Divide each side by -2

-15/-2 = -2a/-2

15/2 =a

8 0

3 years ago

Read 2 more answers