Help me to solve this
2 answers:
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1.Disc method.
In this method the volume is given by:
![\boxed{V=\pi\int\limits_a^b\big[f(x)\big]^2}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%5Cpi%5Cint%5Climits_a%5Eb%5Cbig%5Bf%28x%29%5Cbig%5D%5E2%7D)
so:
![V=\pi\int\limits_1^3x^4\,dx=\boxed{\pi\int\limits_1^3\big[x^2\big]^2\,dx}](https://tex.z-dn.net/?f=V%3D%5Cpi%5Cint%5Climits_1%5E3x%5E4%5C%2Cdx%3D%5Cboxed%7B%5Cpi%5Cint%5Climits_1%5E3%5Cbig%5Bx%5E2%5Cbig%5D%5E2%5C%2Cdx%7D)
A) Function
over the interval ![[1,3]](https://tex.z-dn.net/?f=%5B1%2C3%5D)
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.
2. Shell method.
In this case volume is given by:
</span></span>
So there will be:
A) Function
over the interval
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>
In this method the volume is given by:
so:
A) Function
B) We use disk method and f(x) is function of variable x, so we <span>rotate the curve about the x-<span>axis.
2. Shell method.
In this case volume is given by:
</span></span>
So there will be:
A) Function
B) We use shell method and f(x) is function of variable x, so we <span>rotate the curve about the y-<span>axis.</span></span>
The first step to solving this problem is to decide the best approach to organizing the Nuts and Screws.
I personally would start by separating both groups, this way it becomes easier to know roughly where to look to find what you need. After doing this it would make sense to simply place the bigger Nuts with the bigger Nuts and the bigger screws with the bigger screws, which would leave you with 4 separate groups. The 2 nut groups would be on one side and the 2 screw groups would be on the side.
Now for the number line, I have included the decimal numbers in order down below, we will start with the smallest fraction and begin to plot the points.
*I have also included my graph that I drew on Desmos as well down below*
And now by using everything I have given you the answer to the last question becomes clear ;-) :
4 Screws 1/16” x 3” long
6 Screws 11/64” x 4” long
16 Screws 3/8” x 2” long
1 Screw 7/16” x 3” long
12 Screws 5/64” x 3” long
3 Screws 3/32” x 4” long
1 Screw 1/2” x 3” long
1 Screw 3/4” x 2” long
4 Hex bolts 1.5” x 4” long
DSMT4 4 Hex bolts 1 7/8” x 4” long
1 Hex bolt 2.25” x 2” long
4 Hex bolts 3.75” x 3” long
6 Hex bolts 3 3/8” x 3” long
If you find out that my answer is wrong just let me know, and I guarantee that I will come back and rework my math :-)
Ps. By rating people and giving people Brainliest you not only make them feel good but you get 25% of the points you spent back :-)
