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tatyana61 [14]
3 years ago
14

Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative

3. E is at 2, 4. 1.67 −1.33 0.75 −1.25
Mathematics
2 answers:
Andrej [43]3 years ago
5 0
The answer would be -1.25
LiRa [457]3 years ago
3 1

Answer:

The correct option is 4.

Step-by-step explanation:

It is given that DF and EF form a 1:3 ratio. The coordinates of the end points of the segment DE are D(-3,-3) and E(2,4).

According to the section formula, if a point p divides a line in m:n, then the coordinates of p are

(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})

y value for point F is calculated as

y=\frac{(1)y_2+(3)y_1}{1+3}

The end points of the segment DE are D(-3,-3) and E(2,4).

y=\frac{(1)(4)+(3)(-3)}{4}

y=\frac{4-9}{4}

y=\frac{-5}{4}

y=-1.25

The y- value for point F is -1.25. Therefore the correct option is 4.

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