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Montano1993 [528]
3 years ago
10

Let f(x)=2x+2. Solve f^-1(x) when x=4

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0
F⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.

solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
  x = \dfrac{f(x)-2}{2}
f⁻¹(x) = \dfrac{x-2}{2}

Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) = \dfrac{x-2}{2}
f⁻¹(4) = \dfrac{4-2}{2}
f⁻¹(4) = \dfrac{2}{2}
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
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Equation: -5 3/4- 3 1/2 Please help meh. ​
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Answer:

-9\frac{1}{4}

Step-by-step explanation:

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Step 1: Factor out the common term -1

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Step 2: Add the whole numbers

5 + 3 = 8

Step 3: Combine the fractions:

\frac{3}{4}+\frac{1}{2} = \frac{5}{4}\\\\=-\left(8+\frac{5}{4}\right)

Step 4: Convert the improper fractions to mixed numbers

\frac{5}{4} = 1\frac{1}{4}\\\\=-\left(8+1\frac{1}{4}\right)

Step 5: Add the numbers

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URGENT! 40 POINTS! PLEASE HELP!
umka2103 [35]

Answer:

(a) 8 x(5 x-6)=40 x^{2}-48 x

(c) \begin{aligned}(x-3)(5 x-6) &=5 x^{2}-21 x+18\end{aligned}

Step-by-step explanation:

(a) To find verify the answer we need to multiplying the equation 8 x(5 x-6)

8 x(5 x-6)=40 x^{2}-48 x

Thus, this statement is true.

(b) To find verify the answer we need to multiplying the equation -4 x\left(2 x^{2}+1\right)

-4 x\left(2 x^{2}+1\right)=-8 x^{3}-4 x

Hence, the given statement is false.

(c) To find verify the answer we need to multiplying the equation (x-3)(5 x-6)

\begin{aligned}(x-3)(5 x-6) &=5 x^{2}-6 x-15 x+18 \\&=5 x^{2}-21 x+18\end{aligned}

Hence, the given statement is true.

(d) To find verify the answer we need to multiplying the equation(2 x+3)\left(x^{2}+3 x-5\right)

\begin{aligned}=(2 x+3)\left(x^{2}+3 x-5\right) &=2 x^{3}+6 x^{2}-10 x+3 x^{2}+9 x-15 \\&=2 x^{3}+9 x^{2}-x-15\end{aligned}

Hence, the given statement is false.

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