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Montano1993 [528]
3 years ago
10

Let f(x)=2x+2. Solve f^-1(x) when x=4

Mathematics
1 answer:
Gre4nikov [31]3 years ago
4 0
F⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.

solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
  x = \dfrac{f(x)-2}{2}
f⁻¹(x) = \dfrac{x-2}{2}

Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) = \dfrac{x-2}{2}
f⁻¹(4) = \dfrac{4-2}{2}
f⁻¹(4) = \dfrac{2}{2}
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
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2pi*1=6.28

6.28/2=3.14 because it's a semicircle

3.14*4=12.56 because there are 4 equal semicircles

12.56+4=16.56

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Step-by-step explanation:

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A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu
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Answer:

-0.061 < P_1 -P_2< 0.025

Step-by-step explanation:

Give data:

n_1 = 350

n_2 =250

x_1 = 23

x_2 = 21

\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066

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for 95% confidence interval

\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025

z_{\alpha/2} = 1.96  from standard z- table

confidence interval for P_1  and P_2 is

\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}

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confidence interval is

-0.018 - 0.043 < P_1 -P_2

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