Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
brainly.com/question/1942755
#SPJ4
Each truck weighs five tons.
1st truck: n
2nd truck: n + 2
3rd truck: n + 4
4th truck: n + 6
n + n + 2 + n + 4 + n + 6 = 32
4n + 12 = 32
- 12 - 12
--------------------
4n = 20
---- ------
4 4
n = 5
Quantitative. Because they can be counted
Answer:
A, B, C, & E
Step-by-step explanation:
A) 19,456 ÷ 6 = 3,242 
(2/3 is 0.666666666 etc)
B) 28,765 ÷ 13 = 2,212.692308...
C) 4,145 ÷ 3 = 1,381
(2/3 is 0.666666666 etc)
D) 4,165 ÷ 17 = 245
(Not bolded because it is not an answer)
E) 44,312 ÷ 16 = 2,769.5
C -> When dividing by three, if the first number's values do not add up to a multiple of 3 there will be a remainder. Example from your problem,
4,145 -> 4 + 1 + 4 + 5 = 14 -> 14 is not a multiple of 3, so there is a reminder
D -> No decimal / fraction, no remainder!
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
