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professor190 [17]
3 years ago
10

The correlation coefficient for practicing violin and getting better grades in a group of people is 0.8. Analyze the following s

tatement.
Playing violin causes students to get better grades.

Is this a reasonable conclusion?

Yes; students who play violin must necessarily get better grades

Yes; the correlation coefficient is above 0.5, so that implies causation

No; playing violin and earning better grades are completely unrelated

No; even though there is a strong positive correlation, playing violin doesn't cause students to get better grades
Mathematics
2 answers:
kobusy [5.1K]3 years ago
3 0

Answer: No; even though there is a strong positive correlation, playing violin doesn't cause students to get better grades

Step-by-step explanation:

Causation describes a relationship between two quantities where one quantity is effected by the other.

Given: The correlation coefficient for practicing violin and getting better grades in a group of people is 0.8.

Since 0.8 is near to 1, hence it shows a strong correlation.

But correlation does not imply causation because if just two quantities correlate does not necessarily means that one causes the other.

Hence, the given conclusion is not reasonable .

pogonyaev3 years ago
3 0

Answer:

OPTION D: No; even though there is a strong positive correlation, playing violin doesn't cause students to get better grades.

Step-by-step explanation: I got it right on the test.

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Find all exact solutions on the interval [0, 2π). Look for opportunities to use trigonometric identities.
Nostrana [21]

Answer:

x = π/2, 7π/6, or 11π/6

Step-by-step explanation:

sin² x − cos² x − sin x = 0

Use Pythagorean identity to write cosine in terms of sine.

sin² x − (1 − sin² x) − sin x = 0

sin² x − 1 + sin² x − sin x = 0

2 sin² x − sin x − 1 = 0

Factor:

(2 sin x + 1) (sin x − 1) = 0

Solve:

sin x = -1/2 or 1

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7 0
3 years ago
Read 2 more answers
Suppose the distribution of home sales prices has mean k300, 000 and standard
777dan777 [17]

<u>Given</u>:

Mean,

\mu = 300,000

Standard deviation,

\sigma = 50,000

The Chebyshev theorem will be used for the solution of the given query,

i.e., P(|X - \mu| < k \sigma ) \geq 1-\frac{1}{k^2}

(i)

⇒ 1-\frac{1}{k^2} = 0.75

            k = 2

The lower limit will be:

= \mu - k \sigma

= 300000-2\times 50000

= 200000

The upper limit will be:

= \mu + k \sigma

= 300000+2\times 50000

= 400000

hence,

The 75% houses sold are between:

⇒ (200000, 400000)

(ii)

⇒ \mu -k \sigma = Lower \ limit

By putting the values, we get

   300000-50000k = 150000

   300000-150000=50000k

                  150000=50000k

                           k=\frac{150000}{50000}

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now,

⇒ 1-\frac{1}{k^2} = 1-\frac{1}{3^2}

              =\frac{8}{9}

              =0.8888

              =88.88 (%)

hence,

88.88% houses sold between 150000 and 450000.      

(iii)

⇒ \mu - k \sigma = Lower \ limit

By putting the values, we get

   300000-50000k = 170000

   300000-170000=50000 k

                  130000= 50000 k

                          k = \frac{130000}{50000}

                             =2.6

now,

⇒ 1-\frac{1}{k^2} = 1-\frac{1}{2.6^2}

              =0.8521

              =85.21 (%)

hence,

85.21% houses are sold between 170000 and 430000.

Learn more:

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Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

2q^2+q-2=0

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Using quadratic formula,

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