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zysi [14]
3 years ago
9

The two polygons are similar. Find the values of x and y.

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

  X = 64 and Y= 43

Step-by-step explanation:

 If this was helpful your welcome, but if it's not than im sorry

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The equation for this line is y=1.3x+2
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A box is filled with 6 blue cards, 6 brown cards, and 3 green cards. A card is chosen at random from the box. What is the probab
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2(4x) = 8<br><br> x = ?<br><br> hELP
navik [9.2K]

Answer:

x = 1

Step-by-step explanation:

2(4x) = 8

2(4x) = 2 * 4x

2 * 4x = 8x

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A 500-page book contains 250 sheets of paper. The thickness of the paper used to manufacture the book has mean 0.08 mm and stand
LenaWriter [7]

Answer:

10.20% probability that a randomly chosen book is more than 20.2 mm thick

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.

So for the book.

\mu = 250*0.08 = 20, \sigma = \sqrt{250}*0.01 = 0.158

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)

This is 1 subtracted by the pvalue of Z when X = 20.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20.2 - 20}{0.158}

Z = 1.27

Z = 1.27 has a pvalue of 0.8980

1 - 0.8980 = 0.1020

10.20% probability that a randomly chosen book is more than 20.2 mm thick

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4 years ago
I need help with this question
iogann1982 [59]
The answer is 190 yup
5 0
2 years ago
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