Simplify. Write each answer in scientific notation.

Marina simplified the expression 4x + 5 (-4x -b) - (x -2) to be -17x -8.

S_A_V [24]

Answer:

C.)

Step-by-step explanation:

4x -20x -5b -x +2=-17x -8

-17x-5b+2=- 17x-8

+17x +17x

-5b +2= -8

-2 -2

-5b = -10

b= 2

7 0

2 years ago

Can someone help me for brainllest ITS TIMED AND IM FREAKING OUT

alina1380 [7]

Answer:

1.

If two angles are supplementary, their sum is 180 degrees.

Check: 10 + 170 = 180

=> Maryam's claim is correct

If two angles are complementary, their sum is 90 degrees.

Check: 81 + 9 = 90

=> Ailia's claim is correct

2.

As the definition:

Vertical angles have sides that form two pairs of opposite rays.

Adjacent angles have a common side and don't overlap.

=> As provided pair of angles, they are adjacent pair of angles.

=> Ahmed's statement is wrong, Saalem's statement is correct.

Hope this helps!

:)

8 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Please answer the question below and show working

strojnjashka [21]

Answer:

i. Slope=-1/6

ii. Midpoint= (1,8.5)

iii. Distance= √37 units

iv. Slope of t=2

please see the attached picture for full solution...

Hope it helps..

Good luck on your assignment...

6 0

3 years ago

Divide 3900677 by 3883.66667

coldgirl [10]

The Answer is 100.43781641

4 0

2 years ago