Answer:
Therefore, x is 1 and 2.
Step-by-step explanation:
As you plot both equations on the same graph, you will get something like this, shown in the graph.
Then, you have to find the x solutions where they intersect.
So, both equations intersect at x = 1 and 2.
I don’t understand what the question is telling me
Answer:
x = 16
Step-by-step explanation:
3(x+2)-x=38
Distribute
3x+6 -x = 38
Combine like terms
2x+6 = 38
Subtract 6 from each side
2x+6-6 = 38-6
2x = 32
Divide each side by 2
2x/2 = 32/2
x = 16
The picture is incomplete and the width is missing.
I am going to show you how to do it using any width.
The length shown is x + 4 and the width starts with - x.
Assume the width is - x + a.
Then the area of the rectangle with dimensions x + 4 and - x + a is calculated in this way:
1) given: (x + 4) (- x + a)
2) use distribuitive property: (x)(-x) + (x)(a) + (4)(-x) + (4)(a)
= - x^2 +ax -4x + 4a
3) Combine like terms: - x^2 + (a -4)x + 4a
If the polynomial missing were - x + 7, the answer would be:
- x^2 + (7 -4)x + 4(7) = - x^2 + 3x + 28
With this you are able to get the answer using the real values.
