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3 years ago

Find elapsed time between 7:10 am to 8:15am two way

2 answers:

7 0

First Way:
7: 10am to 8:00am = 50 mins
8:00am to 8:15am = 15 mins
Total = 50 min + 15 min = 65 mins = 1 hour 5 mins

Second Way:
7: 10am to 8:10am = 1 hour
8:10am to 8:15am = 5 mins
Total = 1 hour + 5 mins = 1 hour 5 mins

Answer : 1 hour 5 mins

Nataliya [291]3 years ago

7 0

NOTE each hour has 60 minutes
Distance from 7:10 to 8:00 = 50 minutes
8:00 to 8:15 = 15 minutes
50 + 15 = 65 minutes
65 minutes, Hope this helps!

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An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random

Alex17521 [72]

Answer: 300

Step-by-step explanation:

Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.

i.e, Total CD's he has now = 6,000

Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.

Then , the proportion of defective( D) CD's = $\dfrac{D}{S}=\dfrac{2}{40}=0.05$

Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)

= 6000 x 0.05

=300

Hence, the number of CDs in the shipment are likely to be defective =300

8 0

3 years ago

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Are s^2 ,2s^2 and 3s^2 equivalent

alexira [117]

No they are not quivalent

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3 years ago

I need help on adding fraction in it simplest form?

Llana [10]

It is 6/9. 3 times 3 equals 9, so u have to multiply 2 times 3 and u get six.
2/3=6/9

8 0

3 years ago

Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}

kompoz [17]

Answer:

The ordered pair $(-2,\, -4)$ is indeed a solution to the system:

$\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right.$ .

Step-by-step explanation:

Consider a system of equations about variables $x$ and $y$ . An ordered pair $(x_{0},\, y_{0})$ (where $x_{0}$ and $y_{0}$ are constant) is a solution to that system if and only if all equations in that system hold after substituting in $x = x_{0}$ and $y = y_{0}$ .

For the system in this question, $(-2,\, -4)$ would be a solution only if both equations in the system hold after replacing all $x$ in equations of the system with $(-2)$ and all $y$ with $(-4)$ .

The $\texttt{LHS}$ of the equation $y = (1/2)\, x - 3$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(1/2) \, (-2) - 3$ . The two sides are indeed equal.

Similarly, the $\texttt{LHS}$ of the equation $y = -2\, x - 8$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(-2)\, (-2) - 8$ . The two sides are indeed equal.

Thus, $x = (-2)$ and $y = (-4)$ simultaneously satisfy both equations of the given system. Therefore, the ordered pair $(-2,\, -4)$ would indeed be a solution to that system.

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2 years ago

Esmerelda flips a coin and draws a card. What is the possibility that she gets “heads” and a black card?

elena55 [62]

The possibility of flipping heads is 1 in 2 (1/2)
the possibility of pulling a black card is 26 in 52 (26/52) which equals 1 in 2 (1/2)
multiply those together and you get 1 in 4, 1/4, or a 25%

7 0

2 years ago

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