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astra-53 [7]
3 years ago
14

Linda, Tony, and deon have a total of $99 in their wallets. Tony's has 4 times what deon has. Linda has $9 more than Deon. How m

uch does each have?​
Mathematics
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

Step-by-step explanation:

Let the amount with Deon =$x

The amount with Tony = 4*x = 4x

Amount with Linda = x + 9

x + 4x + x + 9 = $99

6x = 99- 9

6x = 90

x = 90/6

x = 15

amount with Deon = $15

The amount with Tony = 4*15 = $ 60

Amount with Linda = x + 9= 15 + 9 = $ 24

Westkost [7]3 years ago
4 0

Answer:its 9 just ook the tsest

Step-by-step explanation:

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At Friday's football game, 1,294 tickets were sold for a total amount of $8,816.00. If each student ticket costs $5.00, and each
NeTakaya

Answer:

512 student tickets.

Step-by-step explanation:

Let x be number of student tickets and y be number of adult tickets.

We have been given that at Friday's football game 1,294 tickets were sold. We can represent this information as:

x+y=1294...(1)

We are also told that each student ticket costs $5.00, and each adult ticket costs $8.00 and 1,294 tickets were sold for a total amount of $8,816. We can represent this information as:

5x+8y=8,816...(2)

From equation (1) we will get,

y=1294-x

Substituting this value in equation (2) we will get,

5x+8(1294-x)=8,816

5x+10352-8x=8,816

-3x+10352=8,816

-3x=8,816-10352

-3x=-1536

x=\frac{-1536}{-3}

x=512

Therefore, 512 student tickets were purchased at Fridays football game.

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3 years ago
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snow_tiger [21]

Answer:

x = 1.5

Step-by-step explanation:

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Answer:

solution given;

let

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