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3 years ago

7

A proton experiences a force of 4 Newton when it enters perpendicular to the direction of the magnetic field with a speed 100 m/

s. What is the force experienced by the proton if it enters parallel to the direction of the magnetic field with a speed of 200 m/s?

1 answer:

____ [38]3 years ago

7 0

Answer:

F = 0 N

Explanation:

Force on a moving charge in constant magnetic field is given by the formula

$F = q(\vec v\times \vec B)$

so here it depends on the speed of charge, magnetic field and the angle between velocity of charge and the magnetic field

here when charge is moving with speed 100 m/s in a given magnetic field then the force on the charge is given as

$F = 4 N$

now when charge is moving parallel to the magnetic field with different speed then in that case

$\vec v \time \vec B = 0$

so here we have

F = 0

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Diagram for given question is attached below in fig 1

<h3>Part (a) (b)</h3>

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<h3>Part (c) (d)</h3>

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<h3>Part (e) (f)</h3>

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