Answer:
ω₂ = 1.9025 x 10⁻⁶ rad/s
Explanation:
given,
mass of star = 1.61 x 10³¹ kg
angular velocity = 1.60 x 10⁻⁷ rad/s
diameter suddenly shrinks = 0.29 x present size
r₂ = 0.29 r₁
using conservation of angular momentum
I₁ ω₁ = I₂ ω₂





ω₂ = 1.9025 x 10⁻⁶ rad/s
The answer is False, pls. mark me the brainliest if I’m right. THX
Answers:
kinetic energy lost = 86.4J
Explanation:
let Kf be the kinetic energy after the collision and Ki be the kinetic energy before the collision. let the 3kg car be 1 and 2kg car be 2.
Kf = K1(f) + K2(f)
Ki = K1(i) + k2(i)
loss in kinetic energy = Kf - Ki
= 1/2(3)(2.20)^2 + 1/2(2)(2.20)^2 - 1/2(3)(7)^2 - 1/2(2)(-5)^2
= 12.1 - 98.5
= -86.4 J
therefore, the kinetic energy lost in the collision is 86.4 J.
The guy that answered this is fake and he’s doing it for free points so
Just repost it and hope he doesn’t find it
Answer:
Let's start by considering the ideal gas law:

where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature
This equation can also be rewritten as

Now, if we consider a fixed amount of gas, this means that the number of moles (n) is constant. So we can rewrite the equation as

And therefore, if we consider a gas undergoing a certain transformation from 1 to 2, we can write

where 1 indicates the conditions of the gas at the beginning and 2 the conditions of the gas after the process. So, the change in pressure/temperature/volume of the gas can be found by using this equation.