Answer:
Part A
-0.2kgm/s
Part B
+0.12m/s
Part C
-0.08kgm/s
Explanation
Momentum of a body is defined as the product of mass of the body band its velocity.
Momentum = mass × velocity
Change in momentum = m(v-u)
v is the final velocity of the body
u is the initial velocity of the body.
For cart A:
Mass m = 1.0kg
Initial velocity u = +0.70m/s(velocity before collision)
Final velocity' v = +0.5m/s(velocity after collision)
∆Momentum = 1(0.5-0.7)
= 1(-0.2)
= -0.2kgm/s
The x component of the change in the momentum of A is -0.2kgm/s
For cart B:
Similarly;
∆momentum = 0.1(1.6-0.4)
∆momentum = 0.1×1.2
∆momentum = +0.12kgm/s
The x component of the change in the momentum of B is +0.12kgm/s
Part C:
The sum of these two x components of the changes in momentum = (∆momentum)A + (∆momentum)B
= -0.2+0.12
= -0.08kgm/s
Explanation:
It is known that density is the mass present in per unit volume.
Mathematically, Density =
Since, it is given that is 1.18 , is 5.30 , and volume is 2 .
Therefore, mass of air that has entered will be - and it will be calculated as follows.
=
=
= 8.24 kg
Thus, we can conclude that mass of air that has entered the tank is 8.24 kg.
Answer:
Sherpas do work that is much more meaningful than the work other climbers do.
Explanation:
To determine the distance (d) traveled by a body given its speed (S) and the time (t). Use the equation,
S = d / t ; d = S x t
Substituting the known values to the equation,
d = (4 m/s ) x (40 s) = 160 m
Thus, the person will travel 160 meters in 40 seconds.