Answer: ok so this is a true story when i was little and i always like telling story's so here it is...
Explanation: when i was little i had parents that weren't as good and our house was like scary and it had spiders and i was always scared of them so for Christmas me and my 2 sisters got a doll like a American doll and we got princesses and so my older sister Alexis got Cinderella and my other sister heaven she was the second oldest and she got the little mermaid Ariel and i got belle beauty and the beast and so it was getting late and so me and my sister heaven went to put our dolls away in a box and my sister Alexis wanted to put hers in our room we all share a room and a bed and so she decided to put it on this little princess make up dressing table(i found an image that what it kind of looked like ig) siting down and so everyone was sleeping except my older brother he was the oldest and so he wanted to tell my sister Alexis something and our room door was cracked open and before he went to check on her the doll moved and stand up and when down on the floor and walking in circles and my brother saw it and the doll stopped and the dolls head turned facing him and just drooped and so he ran in his room and stayed up all night till someone else woke up soo yea he never liked dolls never and now thats it i know it took ling but yea

It is required an infinite work. The additional electron will never reach the origin.
In fact, assuming the additional electron is coming from the positive direction, as it approaches x=+1.00 m it will become closer and closer to the electron located at x=+1.00 m. However, the electrostatic force between the two electrons (which is repulsive) will become infinite when the second electron reaches x=+1.00 m, because the distance d between the two electrons is zero:

So, in order for the additional electron to cross this point, it is required an infinite amount of work, which is impossible.
I don’t know how to fill this out since there is no picture attached.
Answer:
The number of charges is 1.25 × 10¹⁰
Explanation:
Current is the amount of charge flowing through a conductor per second. The formula for current (I) is given as:
I = Q/t
Where Q is the charge flowing in coulombs and t is the time taken in seconds.
Given that I = 2.0 nA = 2 × 10⁻⁹ A and t = 1 sec
I = Q / t
Q = It = 2 × 10⁻⁹ × 1 = 2 × 10⁻⁹ C
Since each charge = 1.6 x 10⁻¹⁹ C, therefore:
The number of charges = 2 × 10⁻⁹ C / 1.6 x 10⁻¹⁹ C = 1.25 × 10¹⁰
In the single-slit experiment, the displacement of the minima of the diffraction pattern on the screen is given by

(1)
where
n is the order of the minimum
y is the displacement of the nth-minimum from the center of the diffraction pattern

is the light's wavelength
D is the distance of the screen from the slit
a is the width of the slit
In our problem,


while the distance between the first and the fifth minima is

(2)
If we use the formula to rewrite

, eq.(2) becomes

Which we can solve to find a, the width of the slit: