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Diano4ka-milaya [45]

3 years ago

9

Find the median: 7, 4, 5, 2, 7, 7, 2. Need answer asap!!

1 answer:

JulsSmile [24]3 years ago

7 0

Answer:

The answer is 5

Step-by-step explanation:

First arrange the numbers in order :

2, 2, 4 ,5, 7, 7, 7

Then find the middle number :

5

The middle number is 5 , therefore the answer is 5.

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Select the correct answer from each drop-down menu.

sergij07 [2.7K]

Answer:

7.8 and 18.8 is your answer

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Plz help me with this!

nasty-shy [4]

If I’m correct the right answer should be A. 1,680) If I’m wrong plz let me know

8 0

2 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

Are the two events “choosing a sophomore” and “choosing someone who replied ‘Yes’” independent events?

4vir4ik [10]

Yes, they are independent event such that occurring the first event “choosing a sophomore” does not affect the probability of occurring the second event <span>“choosing someone who replied ‘Yes’”</span><span />

5 0

3 years ago

After how many years are the salaries offered by Company A and Company B the same?

iren2701 [21]

Answer:

Step-by-step explanation:

24,000 = 24 thousands

30,000 = 30 thousands

3,000 = 3 thousands

2,4000 = 2.4 thousands

"x" years

24 + 3x = 30 + 2.4x

3x - 2.4x = 30 - 24

0.6x = 6

x = <em>10 years</em>

4 0

2 years ago