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qaws [65]
3 years ago
7

Marla borrowed $200 at a 12% simple interest for one year. If he makes no payments that year, how much interest will he she at t

he end of the year?
a. $6.00
b. $12.00
c. $22.40
d. $24.00
Mathematics
1 answer:
yulyashka [42]3 years ago
3 0
The answer to your question is C. 22.40 
i hope this helped you out
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A coffee shop needs to purchase custom cups. Company C charges a flat fee of $155 plus $15 perrl cup. Company D does not have a
bezimeni [28]

Answer:

11 cups

Step-by-step explanation:

Not really a method just started at 10 and then realised deal d was better so go up by one so 11 and c worked out better as I timed 30 by 11 and 15 by 1 + the flat fee.

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Henrietta is giving her friend Tonya a box of Toblerone chocolate for her birthday. The Toblerone comes in
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Marvin has a vintage comic book worth $351. According to a dealer, the value of this particular comic book will increase by 12.1
White raven [17]
Y = 12.1% x 13 + 351
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3 0
2 years ago
Consider the volume of a rectangular pyramid, one whose base is not square. Does changing one of the three variables (length, wi
user100 [1]

Let

L------> the length of the base of the pyramid

W-----> the width of the base of the pyramid

H-----> the height of the pyramid

V------> Volume of a rectangular pyramid


we know that

V=(1/3)*[L*W]*H

so

the three variables are going to have the same influence on the volume


example

case a) let's change the variable L (we reduce the variable by half)

L=(1/2)*L

the new volume is equal to

V new=(1/3)*[(L/2)*W]*H-----> V new=(1/2)*V

the new volume is half the original volume


case b) let's change the variable W (we reduce the variable by half)

W=(1/2)*W

the new volume is equal to

V new=(1/3)*[(W/2)*L]*H-----> V new=(1/2)*V

the new volume is half the original volume


case c) let's change the variable H (we reduce the variable by half)

H=(1/2)*H

the new volume is equal to

V new=(1/3)*[L*W]*H/2-----> V new=(1/2)*V

the new volume is half the original volume


therefore


the answer is

the three variables have the same influence on the volume

4 0
3 years ago
Read 2 more answers
How do you use the order of operations to evaluate expressions with exponents?
IgorLugansk [536]
Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations
5 0
3 years ago
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