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iren2701 [21]
3 years ago
10

What are the mean and the mode of the following set of data: 5, 12, 1, 5, 7

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
4 0
Mean = ( 5+12+1+5+7) / 5 =  30/5  =  6

mode = 5 
muminat3 years ago
3 0
The mean is 6 and the mode is 5. If you need me to explain just ask. Hope this helps :)
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Find the value of 7w-2 given that - 2w-4=6 .
Vesnalui [34]

Answer:

w= -5

Step-by-step explanation:

  • -2w - 4 = 6
  • -2w - 4 + 4 = 6 + 4
  • -2w = 10

Isolate "w":

  • \frac{-2w}{-2} = \frac{10}{-2}
  • w = -5
4 0
3 years ago
Write a compound inequality for the graph shown below.
irina [24]

A compound inequality for the graph would be:

x >= 0 and x < 2

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A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
An orchard owner wants to plant 64 cherry tree seedlings and 96 peach tree seedlings in rows. Each row is to have the same numbe
-BARSIC- [3]

Answer:

Given:

cherry tree seedlings : 64

peach tree seedlings : 96

64/96 : Simplify this fraction

64 / 8 = 8 / 4 = 2

96 / 8 = 12 / 4 = 3

2 and 3 number of seedlings per row

64 / 2 = 32

96 / 3 = 32

number of rows

The maximum number of rows that the owner can plant is 32 rows with 2 cherry tree seedlings and 3 peach tree seedlings.

5 0
3 years ago
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Estimate the diameter of the supergiant star Betelgeuse, using its angular diameter of about 0.05 arcsecond and distance of abou
8090 [49]

<span>0.05 arc-second = 1 degree/72000 = (pi radians)/(180*72000) = 2.424 x 10^(-7) radians</span>

<span>The distance is roughly: </span>

<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275 light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>

7 0
3 years ago
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