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3 years ago

(help me it is not much)

Mathematics

1 answer:

Harman [31]3 years ago

3 0

Answer:

Slope Intercept Form

Step-by-step explanation:

its the basics

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Let f(x)=4x^2+13x-12 and g(x)=x+4. Perform the function operation F•g(x) Please help!!!

ruslelena [56]

Answer: 4x³+29x²+40x-48

Step-by-step explanation:

To solve f(x)·g(x), you multiply them together.

(4x²+13x-12)(x+4) [distribute by FOIL]

4x³+16x²+13x²+52x-12x-48 [combine like terms]

4x³+29x²+40x-48

Now, we know that f(x)·g(x)=4x³+29x²+40x-48.

4 0

4 years ago

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Pls answer the photo question i need help

g100num [7]

I could be wrong but I think it’s 144,000m for the area

4 0

3 years ago

Oksana_A [137]

Answer:

Step-by-step explanation:

because there are numbers involved

5 0

3 years ago

What is greater, 2/3 or 7/8?

user100 [1]

$\frac{2}{3} = \frac{2 \times 8}{3 \times 8}=\frac{16}{24} \\ \\
\frac{7}{8}=\frac{7 \times 3}{8 \times 3}=\frac{21}{24} \\ \\
16$

7/8 is greater.

7 0

3 years ago

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Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

3 years ago