Answer:
The answer to the system of equations is 4, -4
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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
The area of rhombus is 24 square units.
Step-by-step explanation:
Given,
Length of one diagonal = p = 3+3 = 6 units
Length of other diagonal = q = 4+4 = 8 units
Area of rhombus = 
Area of rhombus = 
Area of rhombus = 
Area of rhombus = 24 square units
The area of rhombus is 24 square units.
Keywords: rhombus, area
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Answer:
lol same
Step-by-step explanation:
