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FrozenT [24]
3 years ago
13

Pls help cause idk how to do this?!!?

Mathematics
1 answer:
tatiyna3 years ago
4 0
U first start of with writing the numbers from small to greatest so it will be 45,53,53,54,60,62,63,67,68 after that your min will be your smallest, 45 and your Max is 68 than for you mid you start off at both ends with your finger ( if needed) to get your middle which in this case, it’s 60. Now for your Q1 u do the exact same thing for mid but instead of you start from 45 to 60 which gets u to 53 as ur Q1. Finally for your Q3 you you starting off at 60 and ending at 68 and doing the same thing again ur Q3 will be 63.
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Ed buys a vase for £24 and adds 25% onto the price before putting it into his shop window.
hoa [83]
The price-tag say 30 £
6 0
3 years ago
PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS
Elina [12.6K]

You want to end up with A\sin(\omega t+\phi). Expand this using the angle sum identity for sine:

A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi

We want this to line up with 2\sin(4\pi t)+5\cos(4\pi t). Right away, we know \omega=4\pi.

We also need to have

\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}

Recall that \sin^2x+\cos^2x=1 for all x; this means

(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}

Then

\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)

So we end up with

2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)

8 0
3 years ago
Read 2 more answers
An angle is five times its supplement. Find both angles.
noname [10]
The measure of the smaller angle is 30 degrees.
The measure of the larger angle is 150 degrees.

What I did:
supplementary angle=180 degrees.
<span>An angle is five times its supplement=180/6=
30
30*5=150
150+30=180

</span>
5 0
3 years ago
Cube-shaped blocks are packed into a cube-shaped storage container. ​ The edge length of the storage container is 212 feet. The
igor_vitrenko [27]

Answer:

The volume of cube-shaped block is 0.125 cubic feet.

Step-by-step explanation:

We are given the following in the question:

Edge length of storage container =

2\dfrac{1}{2}\text{ feet}

Edge length of block =

\dfrac{1}{5}\times \text{Edge length of container}

Putting value we get,

Edge length of block =

\dfrac{1}{5}\times 2\dfrac{1}{2}\\\\=\dfrac{1}{5}\times \dfrac{5}{2}\\\\=\dfrac{1}{2}\text{ feet}

Volume of cube-shaped block = Volume of cube

V = \text{(Edge)}^3\\\\V =(\dfrac{1}{2})^3\\\\V = \dfrac{1}{8}\text{ cubic feet}\\\\V = 0.125\text{ cubic feet}

Thus, the volume of cube-shaped block is 0.125 cubic feet.

7 0
3 years ago
What is the solution to this equation 1^6 x =2
Alenkinab [10]
<h2>Greetings!</h2>

Anything to the power of 1 is still 1, because 1^{6} is simply 1 x 1 x 1 x 1 x 1 = 1 ect.

<h3>So this changes the equation to 1x = 2, which means that:</h3>

x = 2

<h2>Hope this helps!</h2>
8 0
3 years ago
Read 2 more answers
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