Given:
Consider the equation is:

To prove:
by using the properties of logarithms.
Solution:
We have,

Taking left hand side (LHS), we get

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

![[\because \log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog%20x%5En%3Dn%5Clog%20x%5D)

![\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_ab%3D%5Cdfrac%7B%5Clog_x%20a%7D%7B%5Clog_x%20b%7D%5Cright%5D)

Hence proved.
Answer:
1) 11
2) 4
Step-by-step explanation:
1) It is 11 because in the first row we ignore the 0 since it is referring to the first digit, so the first row has 7. In the second row, we ignore the one so it would be 4 because the 9, or would be 19, is above 18.
2) It is 4 because there is one person over 65. In the second row we ignore the 7 and there are 3 people in the 7 row.
2x-8(-7-x)=6
2x+56+8x=6
10x=-50
x=-5
y=-7-(-5)
y=-2
(-5,-2)