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andre [41]
2 years ago
9

One model of a forklift truck can raise a maximum of 1750 kilograms. Write an in equality to describe the maximum number of 40 k

ilogram boxes that this forklift truck can raise
Mathematics
1 answer:
Aneli [31]2 years ago
8 0

Answer:

The forklift truck can raise maximum of 43 boxes.

Step-by-step explanation:

We are given the following in the question:

Maximum limit of  forklift truck =

1750 kilograms

Let x be the number of 40 kilogram boxes that this forklift truck can raise.

Thus, we can write the following inequality that describes the maximum number of boxes raised.

40x \leq 1750\\\\x \leq \dfrac{1750}{40}\\\\x \leq 43.75\\Max(x) = 43

Thus, the forklift truck can raise maximum of 43 boxes.

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If it took 2 hours to clean 4 houses how many houses could be cleaned in 3 hours​
leva [86]

Answer:

6

Step-by-step explanation:

it would be six in one hour he would clean 2 houses in two 4 houses then in three it would be six

8 0
3 years ago
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Why the output is a zero number ?<br><img src="https://tex.z-dn.net/?f=%28x%20-%203%29%20%5Ctimes%20%28x%20%20%20%2B%204%29%20%3
ELEN [110]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 3) × (x + 4) = 0, that is

(x - 3)(x + 4) = 0

The zero product indicates that (x - 3) = 0 or (x + 4) = 0

x - 3 = 0 ⇒ x = 3

x + 4 = 0 ⇒ x = - 4

Thus if x = 3, then

(3 - 3)(x + 4) = 0 × (x + 4) = 0

Similarly if x = - 4 the output is zero

4 0
3 years ago
Suppose a family drives at an average rate of 60 mi/h on their way to visit relatives and then an average rate of 40 mi/h on the
hammer [34]

Answer:

Part A) 2 hours

Part B) d/60 hours

Part C) 48 miles/hour

Step-by-step explanation:

Part A) Let "d" be the distance in miles the family traveled to visit their relatives. How many hours did it take to drive there?

we know that

Let

x ----> the time it take on their way to visit relatives in hours

y ---> the time it take on the way back in hours

we know that

The distance of the way to visit is equal to the distance of the way back

The speed multiplied by the time is equal to the distance

so

60x=40y -----> equation A

y=x+1 -----> equation B

substitute equation B in equation A and solve for x

60x=40(x+1)

60x=40x+40

20x=40

x=2 hours

Find the value of y

y=2+1=3 hours

d=60x

The time it take on their way to visit relatives is 2 hours

The time it take on the way back is 3 hours

Part B) In terms of "d," how many hours did it take to drive there?

we have that

The distance is equal to the speed multiplied by the time

d=60x

Solve for x

x=d/60 hours

Part C) Write and solve an equation to determine the distance the family drove to see their relatives. What was the average rate for the entire trip?

To find the average rate for the whole trip we will need the total distance and the total time

The distance of the way to visit is

d=60x

substitute the value of x

d=60(2)=120 miles

so

The total distance is

120(2)=240 miles

we know that the total time is

2 + 3 =5 hours

The average rate for the complete trip is

240/5=48 miles/hour

5 0
3 years ago
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What is the average rate of change of the function over the interval x = 0 to x = 8?
Hatshy [7]

Answer:

if f(x) = 3x+4, the rate of change is 4.

if f(x) = 2x+7, the rate of change is 2.

Step-by-step explanation:

We know that the average rate of change over the interval x=0 to x=8 is:

(f(x2) - f(x1))/x2-x1

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x2 = 8

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if f(x) = 3x+4

so f(8)=3(8)+4 = 28

f(0)=3(0)+4 = 4

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f(8) = 2(8)+7 = 23

f(0) = 2(0)+7 = 7

Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2

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3 years ago
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TiliK225 [7]
$1,602 for 3 years of Guitar lessons.
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