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allsm [11]
3 years ago
6

Please help with this question.

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

15, 9, 3, -3

Step-by-step explanation:

y= -3x+3

for x= -4, -2, 0, 2 substitute in your equation

y= (-3)*(-4)+3= 12+3= 15

y= -3*-2+3 = 6+3 = 9...

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What is the volume to the nearest tenth of cubic inch.
oee [108]

Answer:

180.6 cubic inches. (Nearest tenth is the same as 1 decimal place)

Step-by-step explanation:

The volume of a cylinder formula is:

V

=

π

r

2

h

The diameter is

10

inches, well half of the diameter is

5

inches which is the radius. Radius is half of the diameter.

If you want the diameter back, just double it.

5

+

5

=

10

.

So we can now plug the numbers into the formula.

V

=

π

(

5

2

)

(

2.3

)

V

=

π

(

25

)

(

2.3

)

(5 Squared =25)

V

=

57.5

π

But if you didn't want it in terms of

π

, so you multiply:

57.5

×

3.14

=180.55

but rounding that to the nearest tenth is the same as rounding to

1 decimal place so you get

180.6 cubic inches.

5 0
3 years ago
Read 2 more answers
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2-cm and a standard dev
Varvara68 [4.7K]

Answer:

The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.

Step-by-step explanation:

We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.

Let \bar X = <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean length of rods = 259.2 cm

           \sigma = standard deviaton = 2.1 cm

           n = sample of steel rods = 17

Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(\bar X > 259 cm)

 

     P(\bar X > 259 cm) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{259-259.2}{\frac{2.1}{\sqrt{17} } } ) = P(Z > -0.39) = P(Z < 0.39)

                                                                = <u>0.65173</u>

The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.

8 0
4 years ago
Convert 17.47° to degrees, minutes, and seconds..
never [62]
For this question, this might help.
17.47 degrees is 17 + 0.47 degrees
If you are using minutes instead of decimal degrees, multiply the fraction by 60. So,

0.47 degrees * 60 minutes per degree= 28.2 minutes

Now you have 17 degrees 28.2 minutes but you can replace fractions of a minute with seconds
 
0.2 minutes * 60 seconds per minute= 12 seconds

So the answer for 17.47º is equal to 17º 28' 12".

I hope this helps.

7 0
3 years ago
A 14.5-gallon gasoline tank is $\frac{3}{4}$
LekaFEV [45]
The answer is in the image. We need 3.625 gallons to fill the tank.

6 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST TO RIGHT ANSWER
ss7ja [257]
From the little marks on the sides, we can see that YZ is the midpoint segment.
YZ is half of VX
12.2 is the answer. 
8 0
3 years ago
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