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OlgaM077 [116]
3 years ago
13

What is the average rate of change of the function over the interval x = 0 to x = 8?

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

if f(x) = 3x+4, the rate of change is 4.

if f(x) = 2x+7, the rate of change is 2.

Step-by-step explanation:

We know that the average rate of change over the interval x=0 to x=8 is:

(f(x2) - f(x1))/x2-x1

Where:

x2 = 8

x1 = 0

if f(x) = 3x+4

so f(8)=3(8)+4 = 28

f(0)=3(0)+4 = 4

Then: (f(x2) - f(x1))/x2-x1 = (28 - 4)/8-0 = 24/8 = 3

On the other hand, if f(x) = 2x+7

f(8) = 2(8)+7 = 23

f(0) = 2(0)+7 = 7

Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2

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The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

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{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

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Part b)

The probability that the student is late given that the professor is on time

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Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

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ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

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