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OlgaM077 [116]
3 years ago
13

What is the average rate of change of the function over the interval x = 0 to x = 8?

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

if f(x) = 3x+4, the rate of change is 4.

if f(x) = 2x+7, the rate of change is 2.

Step-by-step explanation:

We know that the average rate of change over the interval x=0 to x=8 is:

(f(x2) - f(x1))/x2-x1

Where:

x2 = 8

x1 = 0

if f(x) = 3x+4

so f(8)=3(8)+4 = 28

f(0)=3(0)+4 = 4

Then: (f(x2) - f(x1))/x2-x1 = (28 - 4)/8-0 = 24/8 = 3

On the other hand, if f(x) = 2x+7

f(8) = 2(8)+7 = 23

f(0) = 2(0)+7 = 7

Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2

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\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&&  y={{ k }}x
\end{array}\\\\
-------------------------------\\\\
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