Which of these taxes helps provide health insurance for people who are retired or disabled?

A stationary siren emits a sound of frequency 1000 hz and wavelength 0. 343 m. An observer who is moving toward the siren will m

madam [21]

Ummmmmmm I’m not sure just quizlet it. Trust me it helps me A lot

8 0

3 years ago

Read 2 more answers

1. The electric field at the point of charge!

Tju [1.3M]

Answer:so what is your question

Explanation:

6 0

3 years ago

The cj bacteria in the chickens at monita farms have a high frequency of the allele that causes fq resistance. If genetic drift

cestrela7 [59]

If the process of genetic drift was the cause of this phenomenon, then the resistance allele was also present in the original farm.

<h3>What is genetic drift?</h3>

Genetic drift is a genetic phenomenon that occurs when one allele is fixed in a population due to random chance.

Genetic drift is converse to natural selection, where an allele increases this frequency due to evolutionary constraints.

Genetic drift is well known to be the cause of allele fixation by founder population effects.

Learn more about genetic drift here:

brainly.com/question/22924933

3 0

2 years ago

Ben walked into a hardware store and asked the price of some items. The salesman said: One costs $1 Eight costs $1 Seventeen cos

Mars2501 [29]

Ben was buying home address numbers and they cost $1 per digit.

8 0

3 years ago

To compare the average amount of time that canadians and americans spend commuting, a researcher collects a sample of canadians

yKpoI14uk [10]

The standard error of the difference of sample means is 0.444

From the complete question, we have the following parameters

<u>Canadians</u>

Sample size = 50
Mean = 4.6
Standard deviation = 2.9

<u>Americans</u>

Sample size = 60
Mean = 5.2
Standard deviation = 1.3

The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.

This is represented as:

$SE = \frac{\sigma}{\sqrt n}$

The standard error of the Canadian sample is:

$SE_1 = \frac{2.9}{\sqrt{50}}$

So, we have:

$SE_1 = 0.41$

The standard error of the American sample is:

$SE_2 = \frac{1.3}{\sqrt{60}}$

So, we have:

$SE_2 = 0.17$

The standard error of the difference of sample means is then calculated as:

$SE= \sqrt{SE_1^2 + SE_2^2}$

This gives

$SE= \sqrt{0.41^2 + 0.17^2}$

$SE= \sqrt{0.197}$

Take square roots

$SE= 0.444$

Hence, the standard error of the difference of sample means is 0.444