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ella [17]
2 years ago
12

Which of the points lies on the curve y=x^3

Mathematics
2 answers:
dezoksy [38]2 years ago
5 0

Hello,

A: no since (1/3)^3=1/27 not 1/9

B: no since (-1)^3=-1 not 1

C: no since (-2)^3=-8 not -6

D: yes since (-1/2)^3=-1/8

Answser D

ludmilkaskok [199]2 years ago
3 0

Answer:

D

Step-by-step explanation:

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He would want to charge $0.85 per glass of lemonade to cover his expenses and have $10.00 profit. But in reality he would'nt make $17.00 because people don't carry freaking nickels and dimes.
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Consider multiplying 26.2 by 16.43 what would a mathematician say the answer is
IgorC [24]

In mathematics multiplying decimals is just like multiplying a whole number and ignoring the decimals., then just put the decimals in the answer – it is how many decimals does the two numbers combined.

First step:

Line the numbers on the right and do not a line the decimal points

      26.2

×  16.43

Second Step:

Multiply the numbers starting on the right, just like multiplying a whole number and ignore the decimals.

       26.2

<span> ×  16.43</span>

         786

     1048

   1572

<span>+ 262   </span>

   430466

Third step: add the products

        26.2

<span> ×  16.43</span>

         786

     1048

   1572

<span>+ 262   </span>

   430.466 is the mathematician’s answer.

8 0
3 years ago
PLEASE ANSWER THE RIGHT ANSWER PLEASE DO NOT GUESS. PS, ITS MORE THAN ONE ANSWER. :)
Andreas93 [3]

Answer:

c

Step-by-step explanation:

idk lol so I am just putting random thing for this but that's the awnser

4 0
3 years ago
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The figure shows the graph of a quadratic functionſ that has a minimum at the point
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2 years ago
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
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