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My name is Ann [436]
3 years ago
9

Solution to -7+3w=4w-8

Mathematics
1 answer:
Contact [7]3 years ago
8 0
-7 + 3w = 4w - 8

-7 = 4w - 8 - 3w

-7 = w - 8

-7 + 8 = w

1 = w

hope this helped, blessings! :)
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Step-by-step explanation:

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The coordinates for a rectangle are (3,10) (9,10) (9,6) and (3,6). What is the area
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The vertices of Quadrilateral ABCD are located at (1, 4), (5, 0), (2, –3), and (–2, –2).
forsale [732]

Answer:

A - Rectangle B - Square

C - Parallelogram D - Rhombus

Explanation:

We are given

A

(

1

,

2

)

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B

(

2

,

−

2

)

and hence

A

B

=

√

(

2

−

1

)

2

+

(

−

2

−

2

)

2

=

√

17

. Further slope of

A

B

is

−

2

−

2

2

−

1

=

−

4

1

=

−

4

.

Case A -

C

(

−

6

,

−

4

)

,

D

(

−

7

,

0

)

As

C

D

=

√

(

−

7

−

(

−

6

)

)

2

+

(

0

−

(

−

4

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

As

A

B

=

C

D

and

A

B

||

C

D

slopes being equal, ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+6)^2+(y+4)^2-0.08)((x+7)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case B -

C

(

6

,

−

1

)

,

D

(

5

,

3

)

As

C

D

=

√

(

5

−

6

)

2

+

(

3

−

(

−

1

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

Further,

B

C

=

√

(

6

−

2

)

2

+

(

−

1

−

(

−

2

)

)

2

=

√

17

and slope of

B

C

is

−

1

−

(

−

2

)

6

−

2

=

1

4

As

B

C

=

A

B

and they are perpendicular (as product of slopes is

−

1

), ABCD is a square.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-6)^2+(y+1)^2-0.08)((x-5)^2+(y-3)^2-0.08)=0 [-10, 10, -5, 5]}

Case C -

C

(

−

1

,

−

4

)

,

D

(

−

2

,

0

)

As mid point of

A

C

is

(

1

−

1

2

,

2

−

4

2

)

i.e.

(

0

,

−

1

)

and midpoint of

B

D

is

(

2

−

2

2

,

−

2

+

0

2

i.e.

(

0

,

−

1

)

i.e. midpoints of

A

C

and

B

D

are same,

but,

B

C

=

√

(

2

−

(

−

1

)

)

2

+

(

−

2

−

(

−

4

)

)

2

=

√

13

i.e.

A

B

≠

B

C

and hence ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+1)^2+(y+4)^2-0.08)((x+2)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case D -

C

(

1

,

−

6

)

,

D

(

0

,

−

2

)

As mid point of

A

C

is

(

1

+

1

2

,

2

−

6

2

)

i.e.

(

1

,

−

2

)

and midpoint of

B

D

is

(

2

+

0

2

,

−

2

+

(

−

2

)

2

i.e.

(

1

,

−

2

)

i.e. midpoints of

A

C

and

B

D

are same,

and,

B

C

=

√

(

2

−

1

)

2

+

(

−

2

−

(

−

6

)

)

2

=

√

17

i.e.

A

B

=

B

C

and hence ABCD is a rhombus.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-1)^2+(y+6)^2-0.08)(x^2+(y+2)^2-0.08)=0 [-14, 14, -7, 7]}

3 0
3 years ago
Find the length of the third side right triangle
lara31 [8.8K]
It would be 12

12^2 + 9^2 is 225
15^2 is 225
therefore 12^2+9^2=15^2
8 0
3 years ago
C = 4x + 5y, the value of "x" when C = 51 &amp; y = -3 is:<br> =16.5<br> =9<br> =-16.5<br> =13
Oksi-84 [34.3K]

Answer:

16.5

Step-by-step explanation:

Just put in the values of C and y first into the expression.

C = 4x + 5y

Put in values.

51 = 4x + 5(-3)

Evaluate.

51 = 4x + (-15)

Swap positions.

4x + (-15) = 51

Shift (-15) to the other side and change to (+15).

4x = 51 + 15

    = 66

Find x.

x = 66 ÷ 4

x = 16.5

6 0
3 years ago
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