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3 years ago

14

Check the box labeled Show Altitude of Triangle ABC. The altitude divides into and through the point you determined in question

2. Measure and record the side lengths of and . Then measure and record the side lengths of and .

1 answer:

maw [93]3 years ago

7 0

Answer:

Step-by-step explanation:

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Which expression is equal to x + (y + z)?

arsen [322]

X+(y+z) is equal to saying (x+y)+z

This is called the cumulative property when order doesn’t matter or doesn’t change the equation. As in 1+2 is the same as 2+1. No matter which way we get the same answer. This only works with multiplication and addition though. Hope this helps. Any questions please just ask!! Thank you so much!!

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4 years ago

Read 2 more answers

In triangle ABC, AC =24, the measure of angle A = 30 degree , and the measure of angle B = 45 degree . Find the area of this tri

andriy [413]

Answer:

142.932

Step-by-step explanation:

given that in triangle ABC, AC =24

Angle A = 30 and Angle B =45

If we draw altitude from C, we get

h = 24sin 30 = 12

Since BC = h (45, 45,90 triangle)

BC=12

By sine formula for triangle

$\frac{12}{sin30} =\frac{AB}{sin(180-45-30)} \\AB = 24 sin 105 = 23.1822$

Area of triangle

= $1/2 (23.1822)(12)\\= 142.932$

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3 years ago

Help please urgenttt

stiv31 [10]

Answer:

its a

Step-by-step explanation:

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3 years ago

What's the equation to solve this? Can't remember!

Lerok [7]

Arc SCD is two times of angle SED, so arc SCD is 8x+22. Now set 8x+22, 5x-8, and 11x+10 to 360 and solve for x

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3 years ago

Answer as many as you can please (write in slope-intercept form)

RoseWind [281]

Answer: See below

Step-by-step explanation:

For the first one, we are already given our slope. All we need to do is find the y-intercept, b.

y=-2x+b

6=-2(-3)+b

6=6+b

b=0

The slope-intercept form is y=-2x.

For the second one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{1-13}{3-(-6)} =\frac{-12}{9}$

Now that we have our slope, we can plug it into our slope-intercept form to solve for b.

$y=-\frac{12}{9} x+b$

$3=-\frac{12}{9}(1)+b$

$-\frac{9}{4} =b$

The slope-intercept form is $y=-\frac{12}{9} -\frac{9}{4}$ .

For the third one, we are already given the slope, so all we have to do is find b.

$y=-\frac{1}{2}x +b$

$-7=-\frac{1}{2} (-4)+b$

$-7=2+b$

$-9=b$

The slope-intercept form is $y=-\frac{1}{2} x-9$ .

For the last one, we need to first find the slope using $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ .

$m=\frac{-8-2}{3-1}=\frac{-10}{2} =-5$

Now that we have our slope, we can plug it into our slope-intercept form and find b.

$y=-5x+b$

$2=-5(1)+b$

$2=-5+b$

$7=b$

Our slope-intercept form is $y=-5x+7$ .

4 0

4 years ago