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noname [10]
2 years ago
8

Twenty eight slips of paper are numbered 1 through 28 and are distributed among a group of people. A random number generator is

used to select a single number between 1 and 28, inclusively
A fair decision is made using this process

How many people could be in this group?

A. 3
B. 6
C. 7
D. 12
Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0

Answer:

Option C is the correct answer.

Step-by-step explanation:

Since a random number generator is used to select a single number between 1 and 28, inclusively;

For a fair decision to be made during the process, the number of persons in the set must be a divisor of 28.

Let's list the divisors of 28:

The divisors of 28 are {1, 2, 4, 7, 14, 28}

The only option that contains one of the divisors is option C which is 7.

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Answer:

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Step-by-step explanation:

the area of the front face by the width. Vc= 20 cm2 x 10 cm. = 200 cm. Area = 20 cm? 2 ft. The volume of soil in the planter is 36 cubic feet. 6 ft. I draw a rectangular prism and I have a prism with the dimensions of 8 in by 12 in by 20 in.

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3 years ago
-(19-2a^2)-57+4g^2 simplify, and please include step by steps thanks
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2(-17+a^2+2g^2)

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3 years ago
There are 347 students going on a field trip. Each bus holds 44 students. If each bus costs $95, is the total cost of the buses
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2 years ago
Another not so difficult one, Giving Brainliest and 35 points
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Read 2 more answers
Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted
Misha Larkins [42]

Answer:

\frac{15}{28}  is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red = 3 + 5 = 8

Probability of getting blue = \frac{3}{8}

Probability of not getting a blue =\frac{5}{8}

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

<u>First Draw Blue, Second Draw Not Blue:</u>

1st Draw: P(Blue) = \frac{3}{8}

2nd Draw: P(Not\:Blue)=\frac{5}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}

<u>First Draw Not Blue, Second Draw Not Blue:</u>

1st Draw: P(Not\:Blue)=\frac{5}{8}

2nd Draw: P(Not\:Blue)=\frac{3}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}

To get the probability of exactly one blue, we add both of the events:

\frac{15}{56}+\frac{15}{56}=\frac{15}{28}

4 0
2 years ago
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