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GaryK [48]
3 years ago
9

A single microvillus is a rod-like structure that is 1.0 μm in height. it has a hemispherical top approximately 0.1 μm in diamet

er. calculate the surface area of the cylinder that forms the "sides" of the microvillus rod. use 3.14 for π.
Mathematics
1 answer:
andre [41]3 years ago
5 0
The surface area of the cylinder that forms the "sides" of the microvillus rod is given by the area of the curved surface of a cylinder with diameter (d) = 0.1 μm and height (h) = <span>1.0 μm.

The curved surface area of a cylinder is given by 2πrh, where r = d / 2 = 0.1 / 2 = 0.05 </span><span>μm.

Thus, the curved surface area is given by

2(3.14)(0.05)(1.0) = 3.14 \times 10^{-11}\mu m^2

Therefore, </span>the surface area of the cylinder that forms the "sides" of the microvillus rod is 3.14 \times 10^{-11}\mu m^2
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