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slega [8]
4 years ago
11

Help on this please

Mathematics
1 answer:
AveGali [126]4 years ago
5 0
18 11 25 8 4 !!!!!!!!
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What is the minimum number of the data set shown on the box-and-whisker plot?
Dmitriy789 [7]
Hello there, and thank you for posting your question here on brainly.

Short answer: C. 9

Why?

Box and whisker plots are confusing, the line in the middle is the median, but we don't need to do that now. The dots on the lines outside of the box show the largest and the shortest number. The plotted point on the way left is your answer, the line plotted is 9.

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3 0
4 years ago
Henry decorates the top of each cupcake with 3 walnuts.If he has 56 walnuts,is that enough to decorate 2 dozen cupcakes?
Lesechka [4]
No, 56 is not enough to decorate 2 dozen cupcakes. If he was to top 2 dozen cupcakes with 3 walnuts then he would need 72 walnuts.

3•24(2dozen)=72
6 0
3 years ago
Find the product.<br> 31 × 60
jekas [21]

Answer:

1800

Step-by-step explanation:

3x6 is 18. You can't use the 1 cuz if you multiply 0 to anything it's 0

8 0
3 years ago
Read 2 more answers
Use substitution to solve the system. <br><br><br> X= 2y-5<br> 4x+3y=-9
sergey [27]

Step-by-step explanation:

x=2y-5 - equation 1

4x+3y=-9 -equation 2

Replace equation 1 in equation 2

4(2y-5)+3y=-9

8y-20+3y=-9

11y=-9+20

11y=11

y=11/11

y=1

If y=1, therefore x=2(1)-5=-3

x=-3,y=1

6 0
3 years ago
You have 5 55 reindeer, Bloopin, Rudy, Ezekiel, Prancer, and Balthazar, and you want to have 3 33 fly your sleigh. You always ha
sweet-ann [11.9K]

Answer:

60 different ways.

Step-by-step explanation:

We have been given that you have 5 reindeer, Bloopin, Rudy, Ezekiel, Prancer, and Balthazar, and you want to have 3 fly your sleigh. You always have your reindeer fly in a single-file line. We are asked to find the number of ways in which we can arrange reindeer.

We will use permutations to solve our given problem.

The number of way to choose r objects from a set of n objects is ^nP_r=\frac{n!}{(n-r)!}.

Upon substituting our given values in permutations formula, we will get:

^5P_3=\frac{5!}{(5-3)!}

^5P_3=\frac{5!}{2!}

^5P_3=\frac{5\times 4\times 3\times 2!}{2!}

^5P_3=5\times 4\times 3

^5P_3=60

Therefore, you can arrange your reindeer in 60 different ways.

4 0
3 years ago
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