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2 years ago

Please finish this equation and write the answer

Mathematics

1 answer:

olga55 [171]2 years ago

7 0

Given:

The equation is:

$2540=\dfrac{22}{7}r^2(20)$

To find:

The solution for the given equation.

Solution:

We have,

$2540=\dfrac{22}{7}r^2(20)$

It can be written as:

$\dfrac{2540\times 7}{22\times 20}=r^2$

$\dfrac{17780}{440}=r^2$

$\dfrac{889}{22}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{889}{22}}=r$ [Radius cannot be negative]

$r=6.3568145$

$r\approx 6.36$

Therefore, the value of r is about 6.36 cm.

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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

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$\frac{T_7}{T_5} = \frac{40}{160}$

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$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

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So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

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