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patriot [66]
3 years ago
13

Find m∠BAC and m∠DAB in the figure shown below.

Mathematics
2 answers:
masha68 [24]3 years ago
8 0
\angle BAC=\angle DAE=80^{\circ}\\
\angle DAB=180-\angle BAC=180-80=100^{\circ}
Anarel [89]3 years ago
4 0

Answer:

m∠BAC = 80° and m∠DAB = 100°

Step-by-step explanation:

We are given, m∠DAE = 80°.

We have, ∠DAE and ∠BAC are vertical angles.

<em>Since, 'Measure of vertical angles are equal'.</em>

So, m∠BAC = m∠DAE = 80°.

Thus, m∠BAC = 80°.

<em>Moreover, 'Sum of measures of angles in straight line is 180°'.</em>

So, m∠DAB + m∠BAC = 180°

i.e. m∠DAB = 180° -  m∠BAC

i.e. m∠DAB = 180° -  80°

i.e. m∠DAB = 100°

Thus, m∠DAB = 100°

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The tangent theta in a triangle is the ratio of sine theta and cos theta. It can be written as,

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Learn more about the tangent theta here;

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