Answer:
Amount he must have in his account today is $5,617.92
Step-by-step explanation:
Data provided in the question:
Regular withdraw amount = $900
Average annual interest rate, i = 4% = 0.04
Time, n = 7 years
Now,
Present Value = ![C \times\left[ \frac{1-(1+i)^{-n}}{i} \right] \times(1 + i)](https://tex.z-dn.net/?f=C%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1-%281%2Bi%29%5E%7B-n%7D%7D%7Bi%7D%20%5Cright%5D%20%5Ctimes%281%20%2B%20i%29)
here,
C = Regular withdraw amount
Thus,
Present Value =
Present Value = ![900 \times\left[ \frac{1-(1+0.04)^{-7}}{ 0.04 } \right] \times(1 + 0.04)](https://tex.z-dn.net/?f=900%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1-%281%2B0.04%29%5E%7B-7%7D%7D%7B%200.04%20%7D%20%5Cright%5D%20%5Ctimes%281%20%2B%200.04%29)
Present Value = ![936 \times\left[ \frac{1 - 1.04^{-7}}{ 0.04} \right]](https://tex.z-dn.net/?f=936%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1%20-%201.04%5E%7B-7%7D%7D%7B%200.04%7D%20%5Cright%5D)
Present Value = ![936 \times\left[ \frac{1 - 0.759918}{ 0.04} \right]](https://tex.z-dn.net/?f=936%20%5Ctimes%5Cleft%5B%20%5Cfrac%7B1%20-%200.759918%7D%7B%200.04%7D%20%5Cright%5D)
Present Value = 936 × 6.00205
or
Present Value = $5,617.92
Hence,
Amount he must have in his account today is $5,617.92
Answer:
82,125.0675
Step-by-step explanation:
45 money per hour times 35 that ir hours on a week equal 1575 times 52.1429 that is amount of weeks on a year equal 82,125.0675
We can construct the function:
Where 
or 
is ordinate and 
is abscissa.
The function actually represents a line. Since it can have linear form.
Hope this helps.
r3t40
A.) 200+15m=395. This is because the initial price is 200, and after that she will add $15/month. The equation you chose would be exponential, meaning the rate would increase as time passed, which is not the case. Instead, the rate is constant, and the only think that changes is m, the number of months.
b.) I believe it will be easier to answer with ^this equation.
c.) The rate of change would be 15, since the rate is increasing monthly by $15.
d.) Once you solve 209+15m=495, you'll have the answer.
