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artcher [175]
3 years ago
12

Can a fraction be a whole number

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
Yes. 1/1 is a fraction but it can be simplified to 1 which is a whole number.
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96 is 44 percent of what? Step by step
Elena-2011 [213]

Answer:

218.18

Step-by-step explanation:

To find what number 96 is 44% of is we can use the formula:

\frac{part}{whole} =\frac{percent}{100}

Just substitute 94 and 44 into the equation:

\frac{96}{x} =\frac{44}{100}

9600=44x\\218.1818...

Or rounded,

218.18

4 0
3 years ago
HELP HELP HELP HELP
Nadya [2.5K]

Answer:

24

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A tennis ball weights about 56.7 grams. About how many ounces would a dozen tennis balls weight?
liberstina [14]

Nothing "weighs" 56.7 grams. "Gram" is a unit of mass, not force or weight.

On Earth, 28.35 grams of mass weigh about 1 ounce .

1 dozen of anything = 12 of them

If each tennis ball has 56.7 grams of mass, then a dozen of them
have

               (12) x (56.7) = 680.4 grams of mass .

Their weight is    (680.4 grams) x (1 ounce / 28.35 grams) =

                             (680.4 / 28.35)  =  24 ounces.

                                              That's  1.5 pounds. 

5 0
3 years ago
WILL GIVE BRAINLIEST
Bezzdna [24]

Answer:

A

Step-by-step explanation:

its A 13m babyyy,.......

4 0
3 years ago
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the temperature of a cup of coffee obeys newton's law of cooling. The initial temperature of the coffee is 150F and 1 minute lat
natka813 [3]

Answer:

Newton's law of cooling says that:

T(t) = Tₐ + (T₀ - Tₐ)*e^(k*t)

or:

\frac{dT}{dt} = -k*(T - T_a)

in the differential form.

where:

T is the temperature as a function of time

Tₐ  is the ambient temperature, in this case, 70F

T₀ is the initial temperature of the object, in this case, 150F

k is a constant, and we want to find the value of k.

Then our equation is:

T = 70F + (150F - 70F)*e^(k*t)

Now we also know that after a minute, or 60 seconds, the temperature was 135F

then:

135F = 70F + (150F - 70F)*e^(k*60s)

We can solve this for k:

135F = 70F + 80F*e^(k*60s)

135F - 70F = 80F*e^(k*60s)

65F =  80F*e^(k*60s)

(65/80) = e^(k*60s)

Now we can apply the Ln(x) function to both sides to get:

Ln(65/80) = Ln(e^(k*60s))

Ln(65/80) = k*60s

Ln(65/80)/60s = k = -0.0035 s^-1

Then the differential equation is:

\frac{dT}{dt} = -0.0035 s^-1*(T - 70F)

8 0
3 years ago
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