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Norma-Jean [14]

3 years ago

12

Holly wants to add an odd number to 659. Which number could possibly be the sum? Choose all answers that are correct. A. 677 B.

686 C. 704 D. 721

1 answer:

noname [10]3 years ago

3 0

It is B and C because if you add an odd number to another odd number it becomes even.

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Mr West has a picture that is 4 inches wide and 7

Pepsi [2]

Answer:

Step-by-step explanation:

The ratio of new length 7 to the initial length 19 is 2.7

Therefore new width will be 2.7×4 which will be 10.9 or about 11 inches

6 0

3 years ago

Read 2 more answers

4+2(7)= <br><br> 62+8×3= <br><br> 3(2+5)−5(3)+8= <br><br> 24−6+12÷2×3=

Temka [501]

4+2(7)= 18

62+8x3= 86

3(2+5)-5(3)+8= 14

24-6+12÷2x3= 36

Hope this helps you! :D

3 0

3 years ago

Can anybody help me with these two questions

sladkih [1.3K]

Answer:

#1 is 39

#2 is 10 1/2

Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get you a better answer!

Have a great thanksgiving break :)

4 0

2 years ago

The top of a table is in the shape of a trapezoid. It has a height 1.5 feet and the two parallel bases measure 3 feet and 5 feet

Kobotan [32]

The area of a trapezoid if found using the formula

A = (base1 + base2)/2 x height

Area = (3+5)/2 x 1.5

Area = 8/2 x 1.5

Area = 4 x 1.5

Area = 6 square feet.

3 0

3 years ago

Read 2 more answers

Sin0=12/37 find tan0

alexira [117]

Answer:

$\large{ \tt{❃ \: EXPLANATION}} :$

We're provide - Sin θ = $\frac{12}{37}$ which means 12 is the perpendicular & 37 is the hypotenuse [ Since Sin θ = $\tt{ \frac{p}{h}}$ ] . We're asked to find out tan θ ].

$\large{ \tt{❁ \: USING \: PYTHAGORAS \: THEOREM}} :$

$\large{ \tt{❊ \: {h}^{2} = {p}^{2} + {b}^{2} }}$

$\large{ \tt{⇢ {p}^{2} + {b}^{2} = {h}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {h}^{2} - {p}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = {37}^{2} - {12}^{2} }}$

$\large{ \tt{⇢ \: {b}^{2} = 1369 - 144}}$

$\large{ \tt{ ⇢{b}^{2} = 1225}}$

$\large{ \tt{⇢ \: b = \sqrt{1225}}}$

$\large{ \tt{⇢ \: b = 35 \: \text {units}}}$

Now , We know - Tan θ= $\tt{ \frac{perpendicular}{base} }$ . Just plug the values :

$\large{ \tt{➝ \: Tan \: \theta = \frac{p}{b} = \boxed{ \tt{ \frac{12}{35} }}}}$

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5 0

3 years ago