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bekas [8.4K]
3 years ago
10

A road bike has a wheel diameter of 622 mm. What is the circumference of the wheel? Use 3.14 for π?

Mathematics
2 answers:
Alborosie3 years ago
4 0

Answer: answer D is correct

Step-by-step explanation:

Mkey [24]3 years ago
3 0
That would be 1953.08
diameter = <span>circumference/pi, so reverse it and multiply 622 by 3.14</span>
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A ramp for a loading truck is 13 long and covers 12 feet along the level ground. How many feet high is the highest point on the
goblinko [34]

Answer:

5 feet

Step-by-step explanation:

Using pythagoras' theorem a^2 = b^2 + c^2

13^2 = 12^2 + c^2

c^2 = 25

c = 5 feet

8 0
2 years ago
Read 2 more answers
How do i find the roots of this equation: f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
Fantom [35]
The equation is <span>f(x) = 2x5 - 9x4 + 12x3 - 12x2 + 10x - 3 = 0
remark:
the sum of coefficients is = 2-9+12-12+10-3=-7+7=0, so a=1 is a zero of f
f can be written as </span>f(x) = (x-1)Q(x), and f(x) / (x-1)= Q(x)
after euclid's division
Q(x) = 2x4 - 7x3 + 5x2 - 7x +3
so for finding the other roots, making Q(x) for product of factors is a must
4 0
3 years ago
Choose the correct answer.
guapka [62]
The correct answer is c but i am not sure

5 0
3 years ago
Solve by using square root: <br> 4(x-1)^2+2=10
Scilla [17]
4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}

Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}


3 0
4 years ago
Read 2 more answers
Write 81.4 as a fraction.
Maslowich
407 over 5 but it also has to be simplified
7 0
3 years ago
Read 2 more answers
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