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Slav-nsk [51]
3 years ago
10

Name the following aldehyde: CHO A. 1,4-dimethylethanal B. 3,6-dimethylheptanal C. 1,6-dipropylheptanal D. 2,5-dimethylheptanal​

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

Answer:

c. 1,6-dipropylheptanal

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How many millimeters are in 4.06 meters
yarga [219]

Answer is 4060

hope this is helpfulhelpful

4 0
2 years ago
What are the first three terms of the Arithmetic Sequence a_n = 15 – 2(n – 1)?
natulia [17]
N = 15

2( n - 1 )

2( 15 - 1 )

2( 14)

28 ✔️
8 0
3 years ago
How do I figure this out ? Please help me
victus00 [196]
Ahh, the ol' trick word problems.

Okay so lets break this down.

So we have 7,000 square feet of work that must be done.  We can lose the square feet part as it will only interfere with solving the problem.

So lets say we have 7,000 amount of work that needs to be done.

We know that our company can get 35 work done in one hour.  Our company also works 10 hours per day so we can say we get 350 work done per day.

We need to figure out how much of the work we got done in four days so we can multiply it by 4 and get 1400 work in four days.

1400/7000 work has been complete.  Lets simplify this.

14/70 work has been completed.

Now we need to find the percent using our good friend ratios.

14/70 = x/100

Then we use cross multiplication to solve and we get 20/100.

We have 20% of the work done.

Pro Tip: In real life, you can assume that when you are at 20% work done that it wont actually be 20% because your boss will want you to be done within 12 days.  In real life, you would have 60% of it done and on to the next project!

I need a new job...
3 0
4 years ago
Two students created models of the same building. One student used a scale factor of 3 centimeters (cm) = 15 meters (m). The sec
swat32

Answer:

2 cm

Step-by-step explanation:

First student:

Scale factor = 3 cm to 15 m

Height of original building = 20 m

Height of the first student's model = \frac{20*3}{15} = \frac{60}{15} = 4 cm

Second student:

Scale factor = 4.5 cm to 15 m

Height of original building = 20 m

Height of the first student's model = \frac{20*4.5}{15} = \frac{90}{15} = 6 cm

Difference between the heights of the two students' models = 6 cm - 4 cm = 2cm

8 0
3 years ago
Assume that a male gorilla can
Nata [24]

Answer:

no he cannot because king Kong is a movie and nothing else

6 0
2 years ago
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