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Irina18 [472]
3 years ago
5

Which of the following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle? Check

all that apply. A. SSS triangle congruence postulate B. All of the radii of a circle are congruent. C. Any line segment can be extended indefinitely. D. CPCTC
Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

A line that splits an angle into two equal angles.

Step-by-step explanation:

The following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle-

A. SSS triangle congruence postulate

B. All of the radii of a circle are congruent.

D. CPCTC - The full form is corresponding parts of congruent triangles are congruent.

Bad White [126]3 years ago
3 0

The answer for apex users are:

All of the radii of a circle are congruent

CPCTC

SSS triangle congruence postulate

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Peter placed an order with an online nursery for 6 apple trees and 5 azaleas and the order came to $147. The next order for 3 ap
Setler79 [48]

Answer:

$243

Step-by-step explanation:

The first order you made :

6 apple

5 azaleas

And total cast was:

 $147

The secant order you order was:

3 apples

4 azaleas

And total cast was:

$96

The total cast of both orders is:

$243

5 0
2 years ago
Read 2 more answers
Decompose the figure into regions that are closest to each
Korolek [52]

The image is decomposed as follows: H1 and H2. Where original graph is Hx.

<h3>Are the images (attached) valid decompositions of the original graph?</h3>

  • Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
  • H1 ∪ H2 = Hx
  • They have no edges in common.

Hence, {H1 , H2} are valid decomposition of G.

<h3>What is a Graph Decomposition?</h3>

A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx

See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.

Learn more about decomposition:
brainly.com/question/27883280
#SPJ1

7 0
1 year ago
Calculate the length of the unknown side of this right angled triangle
azamat

Answer:

12.04

Step-by-step explanation:

Well to solve for the unknown side "c" we need to use the Pythagorean Theorem formula,

a^2 + b^2 = c^2

We already have a and b which are 8 and 9 so we plug them in.

(8)^2 + (9)^2 = c^2

64 + 81 = c^2

145 = c^2

c = 12.04 rounded to the nearest hundredth.

<em>Thus,</em>

<em>the unknown side is about 12.04.</em>

<em />

<em>Hope this helps :)</em>

8 0
3 years ago
Given that f(x) = x2 − 4x − 3 and g(x) = x+3 over 4 , solve for f(g(x)) when x = 9
borishaifa [10]
9+3 =12
12/4 = 3

(3)2-4(3)-3
6-12-3
-9 is the answer
8 0
3 years ago
Due in an hour please help!!! :(
Anton [14]

Answer:

Step-by-step explanation:

1,7 are same side exterior

1,8 alternate exterior

2,4 none

3,5 same side int

2,6 corrosponding

4,6 same side int

4,7 is none

5,4 alternate int

8,5 vertical

8,7 alternate exterior

7 0
2 years ago
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