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Irina18 [472]
3 years ago
5

Which of the following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle? Check

all that apply. A. SSS triangle congruence postulate B. All of the radii of a circle are congruent. C. Any line segment can be extended indefinitely. D. CPCTC
Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0

Answer:

A line that splits an angle into two equal angles.

Step-by-step explanation:

The following are reasons used in the proof that the angle-bisector construction can be used to bisect any angle-

A. SSS triangle congruence postulate

B. All of the radii of a circle are congruent.

D. CPCTC - The full form is corresponding parts of congruent triangles are congruent.

Bad White [126]3 years ago
3 0

The answer for apex users are:

All of the radii of a circle are congruent

CPCTC

SSS triangle congruence postulate

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Answer:

0.0803 = 8.03% probability that the number who have a high school degree as their highest educational level is exactly 32.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school degree as their highest educational level, or they do not. The probability of an adult having it is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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100 such adults

This means that n = 100

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This is P(X = 32).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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I need the answer for this problem please
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Answer:

B

Step-by-step explanation:

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Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

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D. False

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