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zvonat [6]
4 years ago
5

A cylindrical container contains some sand as shown below. How much more sand must be added for the container to be half full? U

se 3.14 for pi.
785 cubic inches

392.5 cubic inches

235.5 cubic inches

157 cubic inches

Mathematics
1 answer:
ziro4ka [17]4 years ago
5 0

Answer: 785 cubic inches

Step-by-step explanation:

2πR + 2πR is the equation.

2π(5)^2 + 2π(5)(10)

50π + 200π

250 (3.14)= 785 inches cubed

I strongly believe this answer is correct, hope it helps.

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algol13

Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

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3 years ago
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Answer:

20 miles in an hour.

Step-by-step explanation:

4/5=0.8

16/0.8=x/1

cross product

0.8*x=16*1

0.8x=16

x=16/0.8

x=20

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