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GuDViN [60]
3 years ago
13

Anyone know this click to see links will get reported

Mathematics
1 answer:
prohojiy [21]3 years ago
3 0

Answer:

exponents, exponents, parenthesis, parenthesis/exponents, parenthesis.

Step-by-step explanation:

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3x+2y=23<br> 1/2x-4=y<br><br> What should I do for this one...? I dont really understand
Hitman42 [59]

Since you have y alone on one side of the equation......

Use substitution and plug in 1/2x-4 for y in the other equation.


3x+2(1/2x-4)=23\\

Distribute

3x+x-8=23

Combine like terms

4x-8=23

Add 8 to both sides

4x=31

Divide by 4

and x=31/4

Plug this value in for x

31/4*1/2-4=y

Simplify

31/8-4=y

Multiply everything by 8 and simplify

31-32=8y\\-1=8y

Divide.....

y=-1/8


Your answers are:

y=-1/8\\x=31/4



8 0
3 years ago
In a neutral atom that has 18 protons, how many electrons does it have?
Llana [10]
Neutral atoms must have equal numbers of protons and electrons

Solution: 18 electrons
6 0
2 years ago
If sin θ = 2 over 7 and tan θ &gt; 0, what is the value of cos θ?
sergey [27]
Sin θ = 2 / 7
tan θ > 0
cos θ = ?

sin θ = opposite / hypotenuse
tan θ = opposite / adjacent
cos θ = adjacent / hypotenuse

short leg = opposite = 2
hypotenuse = 7
long leg = adjacent = ?

adjacent = √(7² - 2²)
adjacent = √(49 - 4)
adjacent = √45
adjacent = √9 * 5
adjacent = 3 √5

cos θ = adjacent / hypotenuse
cos θ = 3√5 / 7
6 0
3 years ago
Emilio compra 3,6 kg de manzanas a 1,45 euros el kilo ¿Cuánto pagara por las manzanas?
Ad libitum [116K]

Answer:

Emilio compra kg De manzanas a euros el kilo cuanto pagara por Las manzanas

3 0
2 years ago
Hakim deposited $50 in a saving account earning 10% interest, compounded annually . To the nearest cent , how much interest will
Paraphin [41]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill

7 0
3 years ago
Read 2 more answers
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