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zaharov [31]
4 years ago
7

2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock

Physics
2 answers:
Iteru [2.4K]4 years ago
6 0

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero V_{o}=0, and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity V of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

V={V_{o}}^{2}+gt

Where:

g=-9.8 m/s^{2} is the acceleration due gravity (directed downwards)

t=4 s is the time it takes to the rock to fall down the cliff

V=(-9.8 m/s^{2})(4 s)

V=-39.2 m/s This is the rock's final velocity and its negative sign indicates it is directed downwards

Marina CMI [18]4 years ago
6 0

Explanation:

It is given that,

Initial speed of the rock, u = 0

It hits the bottom of the ravine at 4 seconds. Let v is the speed of the rock when it hits the bottom of the cliff. It will move under the action of gravity. Using equation of kinematics as :

v=u+at

a = g

v=u+gt

v=gt

v=9.8\ m/s^2\times 4\ s

v = 39.2 m/s

So, the speed of the rock when it hit the bottom of the cliff is 39.2 m/s. Hence, this is the required solution.

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Given:

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