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scZoUnD [109]
4 years ago
13

Radio transmissions show observers in Houston that the International Space Station is 323 miles away, the Chi- nese space statio

n Tiangong is 462 miles away, and the angle International Space Station–Houston–Tiangong is 109 . How far apart are the two space stations?

Physics
1 answer:
Komok [63]4 years ago
7 0

Answer:

The two space stations are 644.1653 miles far apart.

Explanation:

The distance of Huston and the International Space Station is 323 miles.

The distance of Huston and the Chinese space station Tiangong is 462 miles.

Angle between the two stations = 109⁰

So, applying the law of cosines as;

c² = a² + b² - 2abcosC

From the picture shown below, a = 323 miles and b = 462 miles

So,

c² = 323² + 462² + 2(323)(462)cos109 = 104329 + 213444 - 298452cos109

cos109 = -0.3256

So,

c² = 414948.9712

<u>c = 644.1653 miles</u>

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Zero

Explanation:

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1.A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two seconds. What is its acceleration?
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\huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}

<h3><u>Provided</u><u>:</u><u>-</u></h3>
  • Initial velocity = 15 m/s
  • Final velocity = 10 m/s
  • Time taken = 2 s

<h3><u>To FinD:-</u></h3>
  • Accleration of the particle....?

<h3><u>How</u><u> </u><u>to</u><u> </u><u>solve</u><u>?</u></h3>

We will solve the above Question by using equations of motion that are:-

  • v = u + at
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Here,

  • v = Final velocity
  • u = Initial velocity
  • a = acceleration
  • t = time taken
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<h3><u>Work</u><u> </u><u>out</u><u>:</u></h3>

By using first equation of motion,

⇛ v = u + at

⇛ 10 = 15 + a(2)

⇛ -5 = 2a

Flipping it,

⇛ 2a = -5

⇛ a = -2.5 m/s² [ANSWER]

❍ Acclearation is negative because final velocity is less than Initial velocity.

<u>━━━━━━━━━━━━━━━━━━━━</u>

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