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scZoUnD [109]
4 years ago
13

Radio transmissions show observers in Houston that the International Space Station is 323 miles away, the Chi- nese space statio

n Tiangong is 462 miles away, and the angle International Space Station–Houston–Tiangong is 109 . How far apart are the two space stations?

Physics
1 answer:
Komok [63]4 years ago
7 0

Answer:

The two space stations are 644.1653 miles far apart.

Explanation:

The distance of Huston and the International Space Station is 323 miles.

The distance of Huston and the Chinese space station Tiangong is 462 miles.

Angle between the two stations = 109⁰

So, applying the law of cosines as;

c² = a² + b² - 2abcosC

From the picture shown below, a = 323 miles and b = 462 miles

So,

c² = 323² + 462² + 2(323)(462)cos109 = 104329 + 213444 - 298452cos109

cos109 = -0.3256

So,

c² = 414948.9712

<u>c = 644.1653 miles</u>

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Alinara [238K]
You're walking in one direction, and then the exact opposite of that direction, so you simply have to subtract the two distances. 
200-150=50
You're 50 meters west of where you originally started.
You're west because 200 meters west is greater than 150 meters east. If the distance walked east was greater than the distance walked west, you would've been east of your starting position.
6 0
3 years ago
If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m
musickatia [10]

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ Force=Mass\times Acceleration

or,

⇒       F=ma

⇒    47.0=m\times 3.20

⇒       m=\frac{47.0}{3.20}

⇒           =14.6875 \ kg

4 0
3 years ago
The spectral lines of two stars in a particular eclipsing binary system shift back and forth with a period of 3 months. The line
Sladkaya [172]

Answer:

Explanation:

given

T = 3months = 7.9 × 10⁶s

orbital speed = 88 × 10³m/s

V= 2πr÷T

∴ r = (V×T) ÷ 2π

r = (88km × 7.9 × 10⁶s) ÷ 2π

r = 1.10 × 10⁸km

using kepler's 3rd law

mass of both stars = (seperation diatance)³/(orbital speed)²

M₁ + M₂ = (2r)³/(\frac{1}{4}year)²

= (1.06 × 10²⁵)/(6.2×10¹³)

1.71×10¹²kg

since M₁ = M₂ =1.71×10¹²kg ÷ 2

M₁ = M₂ = 8.55×10¹¹kg

6 0
3 years ago
Walking along a 6-meter beam without falling helps to develop __________.
IrinaVladis [17]
C is correct answer.


Walking along a 6 meter beam without falling helps to develop balance.


Hope it helped.

-Charlie
4 0
3 years ago
Read 2 more answers
17. A distance-time graph indicates that an object moves 120 meters in 5 seconds and then remains at rest for 5 seconds. What is
irina1246 [14]

Answer:

12 m/s

Explanation:

Speed is distance moved per unit time and expressed as

S=d/t

S is speed, d is distance and t is time.

When at rest for five minutes, distance moved is zero hence speed is 0/5=0 m/s

When having moved 120 m for 5 s then speed is

S=120/5=24 m/s

Average speed is the average of these two speeda

Average speed=(24+0)÷2=24/2=12 m/s

Therefore, average speed is 12 m/s

3 0
3 years ago
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