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scZoUnD [109]
3 years ago
13

Radio transmissions show observers in Houston that the International Space Station is 323 miles away, the Chi- nese space statio

n Tiangong is 462 miles away, and the angle International Space Station–Houston–Tiangong is 109 . How far apart are the two space stations?

Physics
1 answer:
Komok [63]3 years ago
7 0

Answer:

The two space stations are 644.1653 miles far apart.

Explanation:

The distance of Huston and the International Space Station is 323 miles.

The distance of Huston and the Chinese space station Tiangong is 462 miles.

Angle between the two stations = 109⁰

So, applying the law of cosines as;

c² = a² + b² - 2abcosC

From the picture shown below, a = 323 miles and b = 462 miles

So,

c² = 323² + 462² + 2(323)(462)cos109 = 104329 + 213444 - 298452cos109

cos109 = -0.3256

So,

c² = 414948.9712

<u>c = 644.1653 miles</u>

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A diagram of a closed circuit with a power source on the left labeled 120 V. There are 3 resistors in parallel, separate paths,
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1) The equivalent resistance is 2.73\Omega

2) The voltage in the circuit is 120 V

3) The total current in the circuit is 44.0 A

Explanation:

1)

Resistors are said to be in parallel when they have the same potential difference at their terminals.

The formula to calculate the equivalent resistance for three resistors in parallel is:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where R_1, R_2, R_3 are the resistances of the three resistors.

In this problem, the resistance of each resistor is:

R_1 = 5.0 \Omega

R_2 = 10.0 \Omega

R_3 = 15.0 \Omega

Substituting,

\frac{1}{R_T}=\frac{1}{5}+\frac{1}{10}+\frac{1}{15}=\frac{11}{30}

So the equivalent resistance is

R_T = \frac{30}{11}=2.73 \Omega

2)

In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

Therefore, the voltage in each branch containing each resistor is the same, and it is equal to the voltage of the battery, which is

V=120 V

So, the voltage in the circuit is 120 V.

3)

The total current in the circuit can be found by using Ohm's law:

V=RI

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V is the voltage

R is the equivalent resistance of the circuit

I is the current

In this circuit, we have:

V = 120 V

R=2.73\Omega

Re-arranging the equation for I, we find the current:

I=\frac{V}{R}=\frac{120}{2.73}=44.0 A

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A concave lens has a focal length of 20 cm. A real object is 30 cm from the lens. Where is the image? What is the magnification?
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