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sveta [45]
3 years ago
11

What is 6 1/4 - 3 1/3

Mathematics
2 answers:
Anettt [7]3 years ago
6 0
Hey There!

Remember, first find the gcf of 4,3 in this problem it is 12.

Steps to solve

1.6\frac{1}{4} - 3\frac{1}{3}

2.6\frac{1}{4} - 3 \frac{1}{3} = 2\frac{11}{12}

So, The answer is <span>2\frac{11}{12}</span>

Hope This Helps :)
Sveta_85 [38]3 years ago
5 0
<span>6 1/4 - 3 1/3

(6 - 3)  1/4  - 1/3

3    1/4 - 1/3          LCM of 4 and 3 is 12.

3    (1/4)*(12/12) - (1/3)*(12/12)        =    3/12 -  4/12


3      3/12 - 4/12

3      (3 - 4)/12

3      -1/12

3    -    1/12

(3*12 - 1) /12

(36 - 1) /12

35/12

2    11/12
</span>
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Alenkasestr [34]

I can't exactly SHOW you where to put the numbers, but I can teach you the process of how you'd do it.

First off, label your number line from 0-15, as it is the simplest. (You'd be counting by 1 per each line). Then, follow this process:

1) Look at the first digit of your value. Place your number according to your first digit. (So, you'd put 0.365 at the 0 line and 3.521 at the 3 line)

2) Look at the second digit of your value. Imagine that between the two main lines (0-1 and 3-4) that there is 10 smaller lines. Then, you can place your number according to your second digit. (So, you'd put 0.365 at the 0.3 line and 3.521 at the 3.5 line).

3) Look at the third digit of your value. Imagine that between the two smaller lines (0.3-0.4 and 3.5-3.6) that there is 10 smaller lines. Then, you can place your number according to your third digit. (So, you'd put 0.365 at the 0.36 line and 3.521 at the 3.52 line).

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jeka57 [31]
A 33 gram sample has k value of .1124
(Actually I think the problem SHOULD be worded: A 33 gram sample has k value of -.1124/days)

See attached graphic:
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Half-Life = <span> <span> <span> 6.1667882562 </span> </span> </span> days

Source:
http://www.1728.org/halflif2.htm





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0 ≠ 4. The equation is wrong, and has no true solution.

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<em><u>Combine like terms.</u></em>

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<em><u>Cancel like terms.</u></em>

<em><u>Subtract 3 from both sides.</u></em>

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Answer:

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Step-by-step explanation:

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