What is the solution of the equation s=-4s+30

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

Step-by-step explanation:

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URGENT!!!!!! Find the value of q in the following system so that the solution to the system is——

valkas [14]

<h3>Answer: Q = 8</h3>

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Explanation:

The left hand side of the first equation is x-3y

The left hand side of the second equation is 2x-6y = 2(x-3y). Note how it's simply double of the first expression x-3y

If we multiply both sides of the first equation by 2, we get

x-3y = 4

2(x-3y) = 2*4

2x-6y = 8

Meaning that 2x-6y = 8 is equivalent to x-3y = 4. Both produce the same line leading to infinitely many solutions. Each solution will lay along the line x-3y = 4.

We can say each solution is in the set {(x,y): x-3y = 4}

Which is the same as saying each solution is of the form (3y+4,y)

4 0

3 years ago

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard devi

kotykmax [81]

Answer:

0.35% of students from this school earn scores that satisfy the admission requirement.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.

This means that $\mu = 1479, \sigma = 302$

The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?

The proportion is 1 subtracted by the pvalue of Z when X = 2294. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2294 - 1479}{302}$