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Tpy6a [65]
3 years ago
5

How do you do that I don’t understand

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0
I think the distance is 8 1/8 feet
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Suppose a certain state university's college of business obtained the following results on the salaries of a recent graduating c
Lerok [7]

Answer:

Following are the responses to the given choice:

Step-by-step explanation:

For point a:

H_0: \mu_1 - \mu_2 = 0\\\\ H_1: \mu_1 - \mu_2 < 0

For point b:

t = -2.953

For point c:

\to  p- value = 0.0021

For point d:

Reject H_o. It could deduce that the pay of higher banking is considerably lower than the pay of higher project management.

7 0
3 years ago
How do I find the length of the third side of the triangle
Stels [109]
U can use the Pythagorean theorem which is (a^2 + b^2 = c^2)  It'll help you a lot
8 0
3 years ago
PLEASE HELP ME MY HOMEWORK IS DUE TODAY!! IF YOU ANSWER IT RIGHT ILL MARK YOU BRAINLIEST!!
PtichkaEL [24]
That answer your looking for is 80
7 0
3 years ago
Angles 4, 5, and 6 are in the ratio 2:5:3. Find the measure of each angle
garri49 [273]

Answer:

The angles 4, 5 and 6 are 36, 90 and 54 respectively.

Step-by-step explanation:

First, let's find the total number of parts:

2 + 5 + 3 = 10

The amount of degrees per part is 180 / 10 = 18.

Now, we multiply that factor to the ratio:

2*18 : 5*18 : 3*18//36:90:54

Thus, the angles 4, 5 and 6 are 36, 90 and 54 respectively.

4 0
3 years ago
Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.
LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

\therefore \: \angle A + \angle C = 180° \\  \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\  \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x =  \frac{176}{4}  \\ \therefore \: x =  44 \\  \\  m\angle A  = (2x + 3) \degree \\  = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle A  =91 \degree}} \\  \\ m\angle  C = (2x + 1) \degree \\  = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle   C=89\degree}}  \\  \\ m\angle  D= (x - 10) \degree \\  = (44 - 10) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle  D =34\degree}}  \\  \\ similarly \\  \\  \huge \red{ \boxed{ \therefore \: m\angle  B  = 146\degree}}   \\  \\

6 0
3 years ago
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