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Ulleksa [173]
3 years ago
12

Solve each system by substitution. 8). -7x-2y=-13 x-2y=11

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0
-7x-2y=-13
x-2y = 11 get x alone
x-2y+2y=11+2y
x= 2y+11 substitute into 1st equation

-7 (2y+11) -2y =-13
-14y -77 -2y = -13
-16y -77 = -13
-16y -77 + 77 = -13 + 77
-16y = 64
-16y/-16 = 64/-16
y = -4

substitute in the 2nd equation

x =2y +11
x = 2(-4) + 11
x = -3 + 11
x = 3

Check work
-7(3) -2(-4) = -13
-21 + 8 = -13
-13 = -13

3 -2(-4) = 11
3 + 8 = 11
11 = 11

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Answer:

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Here we can solve this in 2 ways ,

Method 1 :

{5}^{3}  \times  {5}^{3}

Here the bases are equal. So,

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Method 2 :

{5}^{3}  \times {5}^{3}

Here the exponents are same. So,

=  >  {(5 \times 5)}^{3}  =  {25}^{3}  = 15625

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{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

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( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

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THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

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AREA COVERED BY THE ANGLE IN A SEMI SPHERE

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Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

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Total Area - Area Under Unshaded Part

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