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Ulleksa [173]
3 years ago
12

Solve each system by substitution. 8). -7x-2y=-13 x-2y=11

Mathematics
1 answer:
tatyana61 [14]3 years ago
8 0
-7x-2y=-13
x-2y = 11 get x alone
x-2y+2y=11+2y
x= 2y+11 substitute into 1st equation

-7 (2y+11) -2y =-13
-14y -77 -2y = -13
-16y -77 = -13
-16y -77 + 77 = -13 + 77
-16y = 64
-16y/-16 = 64/-16
y = -4

substitute in the 2nd equation

x =2y +11
x = 2(-4) + 11
x = -3 + 11
x = 3

Check work
-7(3) -2(-4) = -13
-21 + 8 = -13
-13 = -13

3 -2(-4) = 11
3 + 8 = 11
11 = 11

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What is the function written in vertex form?
lys-0071 [83]

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The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

f(x)=a(x-h)^{2}+k

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If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

f(x)=3(x+4)^{2}-6

The vertex is the point (-4,-6)

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case B) we have

f(x)=3(x+4)^{2}-38

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

f(x)=3(x-4)^{2}-6

The vertex is the point (4,-6)

a=3

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The parabola open up, the vertex is a minimum

case D) we have

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4 0
3 years ago
.help me with this please thanks
aev [14]
I would say B . 
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5 0
3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
2 years ago
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