Solve each system by substitution. 8). -7x-2y=-13 x-2y=11
1 answer:
-7x-2y=-13
x-2y = 11 get x alone
x-2y+2y=11+2y
x= 2y+11 substitute into 1st equation
-7 (2y+11) -2y =-13
-14y -77 -2y = -13
-16y -77 = -13
-16y -77 + 77 = -13 + 77
-16y = 64
-16y/-16 = 64/-16
y = -4
substitute in the 2nd equation
x =2y +11
x = 2(-4) + 11
x = -3 + 11
x = 3
Check work
-7(3) -2(-4) = -13
-21 + 8 = -13
-13 = -13
3 -2(-4) = 11
3 + 8 = 11
11 = 11
x-2y = 11 get x alone
x-2y+2y=11+2y
x= 2y+11 substitute into 1st equation
-7 (2y+11) -2y =-13
-14y -77 -2y = -13
-16y -77 = -13
-16y -77 + 77 = -13 + 77
-16y = 64
-16y/-16 = 64/-16
y = -4
substitute in the 2nd equation
x =2y +11
x = 2(-4) + 11
x = -3 + 11
x = 3
Check work
-7(3) -2(-4) = -13
-21 + 8 = -13
-13 = -13
3 -2(-4) = 11
3 + 8 = 11
11 = 11
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Answer:
y = negative (2) Superscript x Baseline + 3
Step-by-step explanation:
An exponential function has a range of y > 0. In order for it to have a range of y < 3, it must be reflected across the x-axis (given a negative multiplier) and must be translated upward 3 units.
That is, for some exponential function y = b^x, you must have something of the form ...
y = -a·b^x +3
Only one answer choice has this form:
