Ask question

Ask question

All categories

3 years ago

9

May someone please help me

2 answers:

Neporo4naja [7]3 years ago

7 0

I believe that is ten right?

pashok25 [27]3 years ago

5 0

I think it is 10
But not sure

You might be interested in

The area of a rectangle is 4x+32. The length is 4. Find the width.

marissa [1.9K]

$\bf \textit{area of a rectangle}\\\\ A=Lw~~ \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ A=4x+32\\ L=4 \end{cases}\implies 4x+32=4w \\\\\\ \cfrac{4x+32}{4}=w\implies \cfrac{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ (x+8)}{~~\begin{matrix} 4 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=w\implies \boxed{x+8=w}$

7 0

4 years ago

Are the figures congruent or not ?

LUCKY_DIMON [66]

They are not congruent

4 0

4 years ago

Find the surface area of the prism. Round to the nearest tenth if necessary.

Anarel [89]

The surface area of the prism according to the segment labels is; 480mm².

<h3>What is the surface area of the prism?</h3>

The prism given in the task content is five-faced and hence, its surface area can be evaluated as follows;

Surface area = 2(0.5×15×8)+(15×9)+(8×9) + (17×9).

Hence, the surface area of the prism upon evaluation is; 480mm².

Read more on surface area;

brainly.com/question/1297098

#SPJ1

6 0

2 years ago

Solve the equation. Then check your solution.<br> 5/9d = 9/10

sdas [7]

Answer:

$d=1.62$

The equation is TRUE.

Step-by-step explanation:

To solve the given equation:

$\frac{5}{9}d=\frac{9}{10}$

You need to find the value of the variable "d". You can apply this procedure:

- Multiply both sides of the equation by 9:

$(9)(\frac{5}{9}d)=(\frac{9}{10})(9)\\\\5d=\frac{81}{10}\\\\5d=8.1$

- Divide both sides of the equation by 5:

$\frac{5d}{5}=\frac{8.1}{5}\\\\d=1.62$

Check the solution substituting the value of "d" into the equation and evaluating:

$\frac{5}{9}(1.62)=\frac{9}{10}\\\\0.9=0.9\ (TRUE)$

3 0

3 years ago

Pleaseeeee help me

vaieri [72.5K]

Answer:

how can i help

Step-by-step explanation:

7 0

3 years ago