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AlekseyPX
3 years ago
14

Can someone anyone please man help me out

Mathematics
1 answer:
zzz [600]3 years ago
5 0

Answer:

2 sqrt(3) -2i

Step-by-step explanation:

If we have the magnitude and the theta

z = |z| cos theta + i |z| sin theta

  = 4 cos 330 + i  4 sin 330

  =4 (sqrt(3)/2) + 4i (-1/2)

  = 2 sqrt(3) -2i


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4/3 t = 9 i need help with this question
Sonja [21]

Answer:

t=27/4

Step-by-step explanation:

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3 years ago
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A system has two failure modes. One failure mode, due to external conditions, has a constant failure rate of 0.07 failures per y
nadya68 [22]

Answer:

0.9177

Step-by-step explanation:

let us first represent the two failure modes with respect to time as follows

R₁(t) for external conditions

R₂(t) for wear out condition ( Wiebull )

Now,

R1(t) = e^{-nt} .....1

where t = time in years = 1,

n = failure rate constant = 0.07

Also,

R2(t)=e^{-(\frac{t}{Q} )^{B} }......2

where t = time in years = 1

where Q = characteristic life in years = 10

and B = the shape parameter = 1.8

Substituting values into equation 1

R1(t) = e^{-(0.07)(1)} \\\\R1(t) = e^{-0.07}

Substituting values into equation 2

R2(t)=e^{-(\frac{1}{10} )^{1.8} }\\\\R2(t)=e^{-(0.1)}^{1.8} }\\\\R2(t)=e^{-0.0158}

let the <em>system reliability </em>for a design life of one year be Rs(t)

hence,

Rs(t) = R1(t) * R2(t)

t = 1

Rs(1) = [e^{-0.07} ] * [e^{-0.0158} ] = 0.917713

Rs(1) = 0.9177 (approx to four decimal places)

5 0
3 years ago
Malorie can work 10 math problems in 3 minutes. At this rate, how many problems can she work in one hour?
lisov135 [29]
D
If you multiply 3 by 10 and add a zero onto the ten in the question that is 100 in half an hour, all you need to do then is multiply that answer by two to get your answer.
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lord [1]

Answer:

D.

Explanation:

PEMDAS method. First do the parentheses. Multiply first, then subtract 12 from that number. Once finished with the parentheses, multiply by 8.

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3 years ago
HELPPPPPPPPPPPPPPPPPP!
Papessa [141]
Answer is answer 17 plus 78
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3 years ago
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